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QveST [7]
3 years ago
9

What is the coefficient of a3 after simplifying this expression? 2a3−10ab2+3a3−ab2−7

Mathematics
1 answer:
Sergio [31]3 years ago
7 0

Answer:

<h3>5</h3>

Step-by-step explanation:

Given the expression

2a^3−10ab^2+3a^3−ab^2−7

We are to find the coefficient of a^3

First is to collect the like terms;

2a^3−10ab^2+3a^3−ab^2−7

= 2a^3+3a^3−10ab^2−ab^2−7

= 5a^3-11ab^2-7

From the resulting equation, you can see that the coefficient of the term having a^3 is 5

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NO LINKS Write an inequality to represent the phrase: The sum of a number and seven less than a number
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Answer:

The sum of a number, which I have named 'n', and 7 can be written as the expression:

n+7

remember the word 'is' in a written problem indicates where you'll most likely use an =,≥,≤ sign. Since they say that it is 'no more than' we know that n+7 is less than or equal to the given number, so we use '≤'.

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Step-by-step explanation:

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3 years ago
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A diagram of a lot of land the scale on the diagram is 1 cm represents 2.5 yards what is the area of the actual lot of land
netineya [11]

In order to determine the area of the lot of land in squared yards, proceed as follow:

Convert the dimensions of the rectangle to yards, by using the given conversion factor:

\begin{gathered} 7\operatorname{cm}\cdot\frac{2.5yd}{1\operatorname{cm}}=17.5yd \\ 15\operatorname{cm}\cdot\frac{2.5yd}{1\operatorname{cm}}=37.5yd \end{gathered}

Next, consider that the area of the lot is the area of a rectangle. Replace the previous values of the length and the width of the rectangle:

A=(17.5yd)(37.5yd)=656.25yd^2

Hence, the area of the lot of land is 656.25 sq yd

5 0
1 year ago
In a running competition, a bronze, silver and gold medal must be given to the top three girls and top three boys. If 15 boys an
denis-greek [22]

Answer:

There are a total of possible 1820 results.

Step-by-step explanation:

Since there are two competitions, one for boys and one for girls, and we want all the possible results we will calculate the possible combinations for the boys and multiply them by the possible combinations for the girls. This is shown below:

Boys = \frac{15!}{3!(15 - 3)!} = \frac{15!}{3!12!} = \frac{15*14*13*12!}{3!12!}\\Boys = \frac{15*14*13}{3*2*1}\\Boys = \frac{15*14*13}{3*2*1}\\Boys = 455

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Total number of possible results:

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3 0
3 years ago
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S=(4πr^3)/3, H=(4πr^3)/6

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