Answer:
<em>m<ZXY - m<WXZ = m<WXY
</em>
Step-by-step explanation:
given:
point Z is in the interior of <WXY creating XZ.
<em>if m<WXZ = 20
</em>
<em> m<WXY = 100
</em>
find:
what would equation would you set up to find the missing angle measure?
solution:
<em>Since Z is interior of <WXY
</em>
<em>
m<ZXY - m<WXZ = m<WXY
</em>
<em><WXY = 100 - 20 = 80°
</em>
therefore, the equation would be <em>m<ZXY - m<WXZ = m<WXY </em>
Answer:
1 : a set each of whose elements is an element of an inclusive set. 2 : division, portion a subset of our community.
Step-by-step explanation:
In mathematics, set A is a subset of a set B if all elements of A are also elements of B; B is then a superset of A. It is possible for A and B to be equal; if they are unequal, then A is a proper subset of B. The relationship of one set being a subset of another is called inclusion
hope this helps
Answer:
lol it so easy man 3(y+4) is the answer
Answer:
Step-by-step explanation:
The surface area of a square pyramid is the sum of the area of the squared base + 4 times the area of each triangular face, therefore:
where:
is the area of the base, where
L is the length of the base
is the area of each triangular face, where
h is the height of the face
Substituting,
For the model in this problem,
L = 12
h = 8
Therefore, the surface area here is:
Answer:
- 12 ft parallel to the river
- 6 ft perpendicular to the river
Step-by-step explanation:
The least fence is used when half the total fence is parallel to the river. That is, the shape of the rectangle is twice as long as it is wide.
72 = W(2W)
36 = W²
6 = W . . . . . . the width perpendicular to the river
12 = 2W . . . . the length parallel to the river
_____
<em>Development of this relation</em>
Let T represent the total length of the fence for some area A. Then if x is the length along the river, the width is y=(T-x)/2, and the area is ...
A = xy = x(T -x)/2
Note that the equation for area is that of a parabola with zeros at x=0 and at x=T. That is, for some fence length T, the area will be a maximum at the vertex of this parabola. That vertex is located halfway between the zeros, at ...
x = (0 +T)/2 = T/2
The corresponding area width (y) is ...
y = (T -T/2)/2 = T/4
Equivalently, the fence length T will be a minimum for some area A when x=T/2 and y=T/4. This is the result we used above.
