-3x/4 + 9/4 = (1/2)^x + 1
-3x/4 - 2^-x = -5/4
(Using log rules)
㏑|-3x/4| - ㏑|2^-x| = ㏑|-5/4|
㏑|3x/4| - x㏑|2| = ㏑|5/4|
e^㏑|3x/4| - e^㏑|2|x = e^㏑|5/4|
|3x/4| - 2x = 5/4
|3x| - 8x = 5
|3x-8x| = 5
|-5x| = 5
|5x| = 5
x=1, -1
Blank 1: 3
Blank 2: 27
Blank 3: 21
you have to distribute the three to everything inside the parenthesis, and because it's directly in front of the parenthesis it's being multiplied.
3(x - 9) = 3x - 27
Now you need to isolate the y, in this e ample you need to add 6 to both sides
the final equation should be:
y = 3x - 21
Answer:
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Step-by-step explanation:
Answer: x^2 - y ^2 − 1.5x + 1.5y
Step-by-step explanation:
