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2 years ago

What is the simplified square root of 130?? I’m really stuck

Mathematics

1 answer:

Svet_ta [14]2 years ago

8 0

Answer:

The square root of 130 would be 11.4017543. Rounding to the nearest tenth, we would get 11.4, because the value 0 is below 5. Rounding 11.4 to the nearest whole number, we would get 11, because the value 4 is below 5. So either 11 or 11.4 works, depending on if you are looking for a decimal or a whole number.

Hope this helps ya :D

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Find the indicated values, where g(t)=t^2-t and f(x)=1+x g(f(2)+3)

sleet_krkn [62]

Answer:

$g(f(2)+3)=30$

Step-by-step explanation:

We have the two functions:

$g(t)=t^2-t\text{ and } f(x)=1+x$

And we wish to find:

$g(f(2)+3)$

First, let’s find f(2) first. So, we will substitute 2 for x for f(x):

$f(2)=1+(2)=3$

Hence, we can now substitute 3 for f(2):

$g(f(2)+3)=g(3+3)=g(6)$

Now, we can find g(6). Substitute 6 for t for g(t):

$g(6)=(6)^2-(6)=36-6=30$

Therefore:

$g(f(2)+3)=30$

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Answer:

Step-by-step explanation:

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ELEN [110]

Answer:

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Step-by-step explanation:

Given ratio of sides = a : b, then

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