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3 years ago

Convert the decimal expansion 0.291666... to a fraction.

2 answers:

8 0

$0.291666...=\dfrac{291.666...}{1000}=\dfrac{291\frac{2}{3}}{1000}=\dfrac{\frac{875}{3}}{1000}=\dfrac{875}{3000}=\dfrac{125\cdot 7}{125\cdot 24}=\boxed{\dfrac{7}{24}}$

NNADVOKAT [17]3 years ago

7 0

Pa arti tu fraction

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cupoosta [38]

Answer:

The value of the test statistic is $z = -1.5$

Step-by-step explanation:

The formula for the test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

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In this problem, we have that:

$\mu = 20, X = 17, \sigma = 6, n = 9$

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{17 - 20}{\frac{6}{\sqrt{3}}}$

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3 years ago

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Step-by-step explanation:

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2 years ago

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Stolb23 [73]

Answer:

Step-by-step explanation:

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2 years ago

Alex wants to fence in an area for a dog park. He has plotted three sides of the fenced area at the points E (1, 5), F (3, 5), a

hram777 [196]

Answer:

$(1,1)$

Step-by-step explanation:

Given: E, F, G, H denote the three coordinates of the area fenced

To find: coordinates of point H

Solution:

According to distance formula,

length of side joining points $(x_1,y_1)\,,\,(x_2,y_2)$ is equal to $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

So,

$EF=\sqrt{(3-1)^2+(5-5)^2}=2\,\,units\\FG=\sqrt{(6-3)^2+(1-5)^2}=\sqrt{9+16}=5\,\,units\\GH=\sqrt{(x-6)^2+(y-1)^2}\\EH=\sqrt{(x-1)^2+(y-5)^2}$

Perimeter of a figure is the length of its outline.

$EF+FG+GH+EH=16\\2+5+\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16-2-5\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9$