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alexandr1967 [171]
4 years ago
8

What is the answer using either the substitution method or elimination method

Mathematics
1 answer:
Sophie [7]4 years ago
8 0

To solve this problem, I am going to use the substitution method.  To do this, we use our first equation given (s=4r-1) and substitute this given value for s (4r-1) and substitute it into the second equation so that we have an equation with only one variable.  This is modeled below:

s = 4r - 1

6r - 5s = -23

6r - 5(4r-1) = -23

Now, we can solve this equation as we would any other equation, using the order of operations outlined by PEMDAS.  To begin, we will distribute the factor of -5 through the parentheses on the left side of the equation.

6r - 20r + 5 = -23

Next, we should combine like terms on the left side of the equation:

-14r + 5 = -23

Next, we should subtract 5 from both sides of the equation to get the variable term alone on the the left side of the equation.  We get:

-14r = -28

Finally, we should divide both sides by -14 to get the variable r alone on the left side of the equation.

r = 2

Now that we know that value for the variable r, we can substitute this value into one of our original equations (either one will work, but I am choosing to use the first one):

s = 4r - 1

s = 4(2) - 1

Now, we can find the value for s by using multiplication and then subtraction to simplify the right side of the equation.

s = 8-1

s = 7

Therefore, your answer is s = 7 and r = 2.

Hope this helps!

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What is the average rate of change of f over the interval -1 on a separate sheet of paper and upload the work as a photo. Show a
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Answer:

Average rate of change for the function f(x)= x^2-x-1 over the interval -1<x<1 is -1

Step-by-step explanation:

We need to find average rate of change of f over the interval -1 < x < 1

The function given is: f(x)= x^2-x-1

The formula used to find average rate of change is:

Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}

We have, a = -1 and b = 1

Finding f(b) when b=1

f(x)=x^2-x-1\\f(1)=(1)^2-(1)-1\\f(1)=1-1-1\\f(1)=-1

Now, finding f(a), when a= -1

f(x)=x^2-x-1\\f(-1)=(-1)^2-(-1)-1\\f(1)=1+1-1\\f(-1)=2-1\\f(-1)=1

Now, putting values and finding average rate of change

Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}\\Average\:rate\:of\:change=\frac{f(1)-f(-1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-(1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-1}{1+1}\\Average\:rate\:of\:change=\frac{-2}{2}\\Average\:rate\:of\:change=-1

So, average rate of change for the function f(x)= x^2-x-1 over the interval -1<x<1 is -1

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3 years ago
Please help me this question will mark you the brainliest if you answer thank you !
kaheart [24]
True, true, false, false, true
3 0
2 years ago
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