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alexandr1967 [171]
3 years ago
8

What is the answer using either the substitution method or elimination method

Mathematics
1 answer:
Sophie [7]3 years ago
8 0

To solve this problem, I am going to use the substitution method.  To do this, we use our first equation given (s=4r-1) and substitute this given value for s (4r-1) and substitute it into the second equation so that we have an equation with only one variable.  This is modeled below:

s = 4r - 1

6r - 5s = -23

6r - 5(4r-1) = -23

Now, we can solve this equation as we would any other equation, using the order of operations outlined by PEMDAS.  To begin, we will distribute the factor of -5 through the parentheses on the left side of the equation.

6r - 20r + 5 = -23

Next, we should combine like terms on the left side of the equation:

-14r + 5 = -23

Next, we should subtract 5 from both sides of the equation to get the variable term alone on the the left side of the equation.  We get:

-14r = -28

Finally, we should divide both sides by -14 to get the variable r alone on the left side of the equation.

r = 2

Now that we know that value for the variable r, we can substitute this value into one of our original equations (either one will work, but I am choosing to use the first one):

s = 4r - 1

s = 4(2) - 1

Now, we can find the value for s by using multiplication and then subtraction to simplify the right side of the equation.

s = 8-1

s = 7

Therefore, your answer is s = 7 and r = 2.

Hope this helps!

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Four Boys and Five Girls went to a water park. The total cost for the group was $144. What was the cost of admission for each pe
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1. The table shows the probabilities of a response chocolate or vanilla when asking a child or adult. Use the formula for condit
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\begin{matrix}&\text{chocolate}&\text{vanilla}&\text{total}\\\text{children}&0.14&0.26&0.40\\\text{adults}&0.21&0.39&0.60\\\text{total}&0.35&0.65&1.00\end{matrix}

a. "Chocolate" and "Adults" (whatever those mean) will be independent as long as

P(\text{chocolate}\cap\text{adults})=P(\text{chocolate})\cdot P(\text{adults})

"Chocolate" has the marginal distribution given by the second column, with a total probability of P(\text{chocolate})=0.35. Similarly, "Adults" has the marginal distribution described by the third row, so that P(\text{adults})=0.60. Then

P(\text{chocolate})\cdot P(\text{adults})=0.35\cdot0.60=0.21

Meanwhile, the joint probability of "Chocolate" and "Adults" is given by the cell in the corresponding row/column, with P(\text{chocolate}\cap\text{adults})=0.21.

The probabilities match, so these events are indeed independent.

Parts (b) and (c) are checked similarly.

b. Yes;


P(\text{children})\cdot P(\text{chocolate})=0.40\cdot0.35=0.14
P(\text{children}\cap\text{chocolate})=0.14

c. Yes;

P(\text{vanilla})\cdot P(\text{children})=0.65\cdot0.40=0.26
P(\text{vanilla}\cap\text{children})=0.26
5 0
3 years ago
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