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Contact [7]
3 years ago
9

I need help with this q8

Mathematics
1 answer:
lbvjy [14]3 years ago
8 0

Answer:

y=5x

Step-by-step explanation:

From (2,10) you rise 25 in the y direction and run 5 in the x direction to get to the next known point (7,35).

Thus, the slope is y=25/5x AKA y=5x

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Daniella has $210 in the bank, and her balance is growing at a rate of $3 each month. Lori has $187 in the bank,but her balance
just olya [345]

Answer: 15 1/3 months

Step-by-step explanation:

Daniella has $210 in the bank, and her balance grows at a rate of $3 each month. This can be written as:

b = 3m + 210 ...... equation i

Lori has $187 in the bank and her balance grows at a rate of $4.50 each month. This can be written as:

b = 4.5m + 187 ....... equation ii

Combine both equations

b = 3m + 210

b = 4.5m + 187

3m + 210 = 4.5m + 187

4.5m - 3m = 210 - 187

1.5m = 23

m = 23/1.5

m = 15 1/3 months

4 0
3 years ago
Arrange the following numbers in order from greatest to least 7,361; 7,136; 7,613
d1i1m1o1n [39]
7,613 ,7,361,7,136

 hope that helped
3 0
3 years ago
Read 2 more answers
Hiiii.. please help me with this limit question ​
Alenkasestr [34]

Answer:

π

Step-by-step explanation:

Solving without L'Hopital's rule:

lim(x→0) sin(π cos²x) / x²

Use Pythagorean identity:

lim(x→0) sin(π (1 − sin²x)) / x²

lim(x→0) sin(π − π sin²x) / x²

Use angle difference formula:

lim(x→0) [ sin(π) cos(-π sin²x) − cos(π) sin(-π sin²x) ] / x²

lim(x→0) -sin(-π sin²x) / x²

Use angle reflection formula:

lim(x→0) sin(π sin²x) / x²

Now we multiply by π sin²x / π sin²x.

lim(x→0) [ sin(π sin²x) / x² ] (π sin²x / π sin²x)

lim(x→0) [ sin(π sin²x) / π sin²x] (π sin²x / x²)

lim(x→0) [ sin(π sin²x) / π sin²x] lim(x→0) (π sin²x / x²)

π lim(x→0) [ sin(π sin²x) / π sin²x] [lim(x→0) (sin x / x)]²

Use identity lim(u→0) (sin u / u) = 1.

π (1) (1)²

π

Solving with L'Hopital's rule:

If we plug in x = 0, the limit evaluates to 0/0.  So using L'Hopital's rule:

lim(x→0) [ cos(π cos²x) (-2π cos x sin x) ] / 2x

lim(x→0) [ -π cos(π cos²x) sin(2x) ] / 2x

-π/2 lim(x→0) [ cos(π cos²x) sin(2x) ] / x

Again, the limit evaluates to 0/0.  So using L'Hopital's rule one more time:

-π/2 lim(x→0) [ cos(π cos²x) (2 cos(2x)) + (-sin(π cos²x) (-2π cos x sin x)) sin(2x) ] / 1

-π/2 lim(x→0) [ 2 cos(π cos²x) cos(2x) + π sin(π cos²x) sin²(2x) ]

-π/2 (-2)

π

8 0
3 years ago
Can someone pleast help me with this
ki77a [65]
You should do sport because it gives you a lot of exercise and makes your body healthy. Sports are important because it makes people happy and it shows from studies that oscillatory increases a lot from sports. Sports are fun and exciting and it boots blood flow to the brain. It controls your body weight and it even makes u gain more skills! Kids have a way of breaking bones but sports help bones strengthen. And sports help with anxiety and even depression! I think kids playing sports are a great ideas because every kid needs some fun once and a while
8 0
2 years ago
If 1st and 4tg terms of G.p are 500 and 32 respectively it's second term is ?
bixtya [17]

Answer:

T_{2} = 200

Step-by-step explanation:

Given

Geometry Progression

T_1 = 500

T_4 = 32

Required

Calculate the second term

First, we need to write out the formula to calculate the nth term of a GP

T_n = ar^{n-1}

For first term: Tn = 500 and n = 1

500 = ar^{1-1}

500 = ar^{0}

500 = a

a = 500

For fought term: Tn = 32 and n = 4

32 = ar^{4-1}

32 = ar^3

Substitute 500 for a

32 = 500 * r^3

Make r^3 the subject

r^3 = \frac{32}{500}

r^3 = 0.064

Take cube roots

\sqrt[3]{r^3} = \sqrt[3]{0.064}

r  = \sqrt[3]{0.064}

r = 0.4

Using:  T_n = ar^{n-1}

n = 2     r = 0.4     and a = 500

T_{2} = 500 * 0.4^{2-1}

T_{2} = 500 * 0.4^1

T_{2} = 500 * 0.4

T_{2} = 200

<em>Hence, the second term is 200</em>

5 0
3 years ago
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