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BabaBlast [244]
3 years ago
8

jackrabbits are capable of reaching speeds up to 40 miles per hour. How fast is this in feet per second? (Round to the nearest w

hole number.)
Mathematics
2 answers:
S_A_V [24]3 years ago
8 0
5,280 feet = 1 mile
__ feet per second
59
Alex Ar [27]3 years ago
7 0
40 mi       1 hr               5280 ft
--------- * -------------- * ------------
    hr        3600 sec        1 mi

All but "ft" and "sec" cancel out.  Please reduce this expression.
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x=6

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In one baseball season, Peter hit twice the difference of the number of home runs Alice hit and 6. Altogether, they hit 18 home
saw5 [17]
Below is the solution:

There are two equations to be solved here.  The first one we assign variables to the home runs Peter hits, P, and Alice hits, A. P=2*(A-6) The second equation is the sum of both players home runs.P + A = 18Solving for P yieldsP=18-A We substitute the solution for P into the first equation and solve for A.(18-A) = 2*(A-6)18 - A = 2A - 123A = 30A = 10 Now that A is known, we can plug it into either equations for P to find how many home runs Peter hitsP=18 - (10) = 8orP=2((10)-4) = 8
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3 years ago
3. Two balls are drawn in succession without replacement from an urn containing 4 red balls and 3 blue balls. Find the probabili
choli [55]

Answer:

X ____ 0 ______ 1 _______ 2

P(x) __ 1/7 _____ 4/7 _____ 2/7

Step-by-step explanation:

Given that :

Number of red balls = 4

Number of Blue balls = 3

Total number of balls = (4 + 3) = 7

Picking without replacement :

Number of picks = 2

1st pick is red :

Probability = (required outcome / Total possible outcomes)

USing combination formula :

nCr = n! / (n-r)! r!

Total possible outcome :

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X = number of red

For red = 0;

P(x =0) = required outcome / Total possible outcomes

P(x = 0)

Required outcome : [4C0 * 3C2)]

P(x = 0) = [(4C0 * 3C2)] / 21 = (1*3)/21 = 3/21 = 1/7

P(x = 1)

Required outcome : [4C1 * 3C1)]

P(x = 1) = [(4C1 * 3C1)] / 21 = (4*3)/21 = 12/21 = 4/7

P(x = 2)

Required outcome : [4C2 * 3C0)]

P(x = 2) = [(4C2 * 3C0)] / 21 = (6*1)/21 = 6/21 = 2/7

Hence ;

X ____ 0 ______ 1 _______ 2

P(x) __ 1/7 _____ 4/7 _____ 2/7

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