Its an ore of uraninte i think.
Answer:
P₂ = 16.6 atm
Explanation:
Given data:
Initial pressure = 13.0 atm
Initial temperature = 20.0°C (20+273 = 293 K)
Final temperature = 102.0°C (102+273 =375 K)
Final pressure = ?
Solution:
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
13.0 atm / 293 K = P₂/375 K
P₂ = 13.0 atm × 375 K / 293 K
P₂ = 4875 atm. K /293 K
P₂ = 16.6 atm
Answer:easy
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