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gladu [14]
3 years ago
6

When using ph paper, the ph of a solution can be determined by looking at the _______ of the paper?

Chemistry
1 answer:
Scorpion4ik [409]3 years ago
7 0
The colour of the paper
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Change 0.00765 kL into mL
bagirrra123 [75]

Answer:

7650

Explanation:

formula- multiply the volume value by 1e+6

4 0
4 years ago
Read 2 more answers
Find the percent composition of each element in KMnO4
VARVARA [1.3K]
The way you want to find the percent composition would be by breaking down the problem like so:

K= atomic mass of K which is 39.098
Mn = atomic mass of Mn which is 54.938
O= atomic mass of o which is 15.999

Then you want to add 39.098+ 54.938+ 15.999 and you get 110.035 which is the molar mass for KMnO

Then you want to take each molar mass and then divide it 110.035 and multiply by 100

Ex. K = 39.098/ 110.035 and the multiply what you get by a 100

You do this for the other elements as well good luck!


6 0
3 years ago
¿Cuál era su juego favorito cuando eran niños?​
blagie [28]

Answer:

mi juego favorito probablemente sería Mine craft cuando era más joven, aunque sigue siendo uno de mis juegos favoritos

Explanation:

7 0
3 years ago
If I have 17 liters of gas at 67C and 88.89 atm, what will be the pressure of the gas if I raise the temperature to 94C and decr
dmitriy555 [2]

Answer:

The correct answer is A. 140 atm

Explanation:

We use the gas formula, which results from the combination of the Boyle, Charles and Gay-Lussac laws. According to which at a constant mass, temperature, pressure and volume vary, keeping constant PV / T. We convert the unit Celsius into Kelvin:

0 ° C = 273K, 67 ° C = 273 + 67 = 340K; 94 ° C = 273 + 94 = 367K

P1xV1 /T1= P2x V2/T2

P2= ((P1xV1 /T1)xT2)/V2

P2=((88,89atm x 17L/340K)x367K)/12L= <em>135,927625 atm</em>

7 0
3 years ago
Write the equilibrium expression for N2 (g) + 3 H2 (g) ↔ 2 NH3 (g) + heat I have no idea where to even start, due to the corona
motikmotik

Answer:

The expression of an equilibrium constant will given as:

K_c=\frac{[NH_3]^2}{[N_2][H_2]^3}

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{eq}

K is the constant of a certain reaction when it is in equilibrium

N_2 (g) + 3 H_2 (g)\rightleftharpoons 2 NH_3 (g) + heat

The expression of an equilibrium constant will given as:

K_c=\frac{[NH_3]^2}{[N_2][H_2]^3}

5 0
3 years ago
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