B. The writer didn't mention anything significant .
The specific process by which the water leaves the cell is called <u>plasmolysis.</u>
<h3>What is plasmolysis?</h3>
Plasmolysis is the process in which the cell loses the water that is present inside it because the environment of the cells produces pressure to build up inside the cell. If a cell is present in a hypertonic solution means that solvent concentration is lower in the surrounding solution, then water comes out of the cell while on the other hand, if a cell is present in a hypotonic solution in which the solvent concentration is higher in the surrounding solution, then water goes inside of the cell. The movement of liquid inside or outside of the cell occurs due to the semi-permeable membrane of the cell.
So we can conclude that the specific process by which the water leaves the cell is called <u>plasmolysis.</u>
Learn more about cell here: brainly.com/question/13123319
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The examples of levers are seesaw, door and corkscrew
Answer: Option A, B, and C
<u>Explanation:</u>
A simple machine which is capable of rotating or moving with respect to a fixed point at the center of mass is termed as lever. Lever is made up of a rigid rod which acts as the beam or the object on which the effort can be applied based on the load and a fixed hinge like thing named as fulcrum or the center of mass.
The fulcrum will be fixed and the beam will be rotating or moving with the support of fulcrum at the center for given load or effort. So among the given options, ramp is not falling under the categories of lever as door also have a fulcrum. But the ramp is only an inclined plane without fulcrum. But the Seesaw, door and the corkscrew has both fulcrum and beam which confirms them falling in the category of lever.
When it comes to this equation, I always stick to good ol' momma bears solutions! Tell that boy to put the rock down, rocks are dangerous!!
From- MommaBoi101
To determine the number of gold bars that would fit in the vault, determine the volume (v) of a single gold bar.
v = l x h x w
where l, h, and w are length, height and width, respectively. Substituting the known values,
v = (6 cm)(2 cm)(3 cm) = 36 cm³
The number of gold bars can be determined by dividing the volume of the vault by the volume of the gold bar,
n = (500 cm³ / 36 cm³) = 13.89
Thus, the maximum number of gold bars in the vault is 13.
