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1 year ago

Light hits ocean during

Physics

1 answer:

Lostsunrise [7]1 year ago

4 0

Answer:

no way to tell since the ocean surface is moving too violently it's not possible to determine the reflected angle

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The equation for the speed of a satellite in a circular orbit around the earth depends on mass. Which mass?

katovenus [111]

<h3><u>Question: </u></h3>

The equation for the speed of a satellite in a circular orbit around the Earth depends on mass. Which mass?

a. The mass of the sun

b. The mass of the satellite

c. The mass of the Earth

<h3><u>Answer:</u></h3>

The equation for the speed of a satellite orbiting in a circular path around the earth depends upon the mass of Earth.

Option c

<h3><u> Explanation: </u></h3>

Any particular body performing circular motion has a centripetal force in picture. In this case of a satellite revolving in a circular orbit around the earth, the necessary centripetal force is provided by the gravitational force between the satellite and earth. Hence $F_{G} = F_{C}$ .

Gravitational force between Earth and Satellite: $F_{G} = \frac{G \times M_e \times M_s}{R^2}$

Centripetal force of Satellite : $F_C = \frac{M_s \times V^2}{R}$

Where G = Gravitational Constant

$M_e$ = Mass of Earth

$M_s$ = Mass of satellite

R= Radius of satellite’s circular orbit

V = Speed of satellite

Equating $F_G = F_C$ , we get

Speed of Satellite $V =\frac{\sqrt{G \times M_e}}{R}$

Thus the speed of satellite depends only on the mass of Earth.

6 0

3 years ago

What does the area between the line and the x axis represent on a velocity vs time graph

pychu [463]

the area bounded by the line and the axes of a velocity-time graph is equal to the displacement of an object during that particular time period

Thank you

5 0

3 years ago

In a oxidation-reduction reaction, the oxidizing agent always undergoes reduction.

Free_Kalibri [48]

In a oxidation-reduction reaction, the oxidizing agent always undergoes reduction.

TRUE.

6 0

3 years ago

Read 2 more answers

A professor drives off with his car (mass 870 kg), but forgot to take his coffee mug (mass 0.47 kg) off the roof. The coefficien

SSSSS [86.1K]

Answer: $6.86 m/s^2$

Explanation:

Given

mas of car=870 kg

coffee mug mass=0.47 kg

coefficient of static friction between mug and roof $\mu _s= 0.7$

Coefficient of kinetic Friction $\mu _k=0.5$

maximum car acceleration is $\mu \times g$

here coefficient of static friction comes in to action because mug is placed over car . If mug is moving relative to car then \mu _k is come into effect

$a_{max}=0.7\times 9.8=6.86 m/s^2$