All categories

3 years ago

Maddy and Caitlin spend a certain amount of money from their money box each month to buy bracelet-making supplies.

2 answers:

fomenos3 years ago

8 0

Solutions

We know that Function 1 shows a greater rate of change, because Maddy spends $20 each month and Caitlin spends $18.

Maddy spends 2 dollars more.

Therefore the correct answer is the last option.

Oxana [17]3 years ago

8 0

Function 1 shows a greater rate of change, because Maddy spends
$20 each month and Caitlin spends $18 each month (last choice).

You might be interested in

A rule for a sequence of numbers is given.

Sliva [168]

D u got to add a lil bit and that you do division

6 0

3 years ago

A jewelry manufacturer makes pendants with 1 and 1/2 ounces of silver in each. It has

Brilliant_brown [7]

Do repeated addition to 1 and 1/2 to get the answer

8 0

2 years ago

13. What is the highest number of degrees that an angle can have? 180 360 90 270

kykrilka [37]

Answer:

360

Step-by-step explanation: A full angle is 360. 90*4=360.

8 0

2 years ago

For a party, you are cooking a large amount of stew that has meat, potatoes, and carrots. The meat costs $6 per pound, the potat

Vaselesa [24]

Answer:

6lb meat

2.5lb potatoes

5Ib carrots

Step-by-step explanation:

M + P + C = 13.5

6M + 3P + C = 48.50

OM + 2P - C = O

2P = C

Therefore, there are 6 pounds of meat, 2.5 pounds of potatoes, and 5 pounds of carrots.

7 0

3 years ago

Determine what must be multiplied so that the expression below will have a common denominator. Use the backslash / to type in a

Mashutka [201]

Answer:

Multiply the first fraction by $\frac{x+4}{x+4}$

Multiply the second fraction by $\frac{x-4}{x-4}$

Step-by-step explanation:

Given

$\frac{4}{x^2 - 16} + \frac{3}{x^2 + 8x + 16}$

Required

Make the denominator equal

$\frac{4}{x^2 - 16} + \frac{3}{x^2 + 8x + 16}$

Factorize the denominator

$\frac{4}{x^2 - 4^2} + \frac{3}{x^2 + 4x + 4x+ 16}$

$\frac{4}{(x - 4)(x + 4)} + \frac{3}{(x+ 4)(x + 4)}$

Multiply the first fraction by $\frac{x+4}{x+4}$

Multiply the second fraction by $\frac{x-4}{x-4}$

$\frac{x+4}{x+4} * \frac{4}{(x - 4)(x + 4)} + \frac{3}{(x+ 4)(x + 4)} * \frac{x-4}{x-4}$

$\frac{4(x + 4)}{(x - 4)(x + 4)(x + 4)} + \frac{3(x - 4)}{(x+ 4)(x + 4)(x - 4))}$

$\frac{4(x + 4)}{(x^2 - 16)(x + 4)} + \frac{3(x - 4)}{(x^2 - 16)(x + 4))}$

The expression now have the same denominator

7 0

3 years ago