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3 years ago

15

PLEASE ANSWER!! Which unit of measure would be MOST appropriate to use when finding the weight of an Orange

1 answer:

koban [17]3 years ago

7 0

Answer: ounces

Step-by-step explanation:

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The coordinates of the vertices of trapezoid JKLM are J(2, −3) , K(6, −3) , L(4, −5) , and M(1, −5) . The coordinates of the ver

olga2289 [7]

This is your answer:
<span>Trapezoid JKLM is congruent to trapezoid J′K′L′M′ because you can map trapezoid JKLM to trapezoid J′K′L′M′ by reflecting it across the line y = x and then translating it 1 unit up, which is a sequence of rigid motions.</span>

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3 years ago

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Due to a membership drive for a public television station, the current membership is 125% of what it was a year ago. The current

Oliga [24]

$x(1.25)=1200$

$\frac{x(1.25)}{1.25}=\frac{1200}{1.25}$

$x=960$

8 0

2 years ago

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18.96 x 2.03 correct to 2 significant figures equals what?

Andreas93 [3]

9514 1404 393

Answer:

38

Step-by-step explanation:

The product of the given numbers is 38.4888. Rounding this to two significant digits gets you 38.

6 0

2 years ago

What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove

wolverine [178]

Answer:

The solutions are:

$b=0,\:b=4$

Step-by-step explanation:

Considering the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

Solving the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

$\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c$

$5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2$

$5b^3-10=6b^3-4b^2-10$

$\mathrm{Switch\:sides}$

$6b^3-4b^2-10=5b^3-10$

$6b^3-4b^2-10+10=5b^3-10+10$

$6b^3-4b^2=5b^3$

$\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}$

$6b^3-4b^2-5b^3=5b^3-5b^3$

$b^3-4b^2=0$

$Using\:the\:Zero\:Factor\:Principle:$ $if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

So,

$b=0,b-4=0$

$b=0,b=4$

Therefore, the solutions are:

$b=0,\:b=4$

4 0

3 years ago

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Can someone help me find the slope

julia-pushkina [17]

The slope is rise over run so it would be -1/3

4 0

2 years ago