Yes, its quadratic. constant may be zero.
Answer:
600
Step-by-step explanation:
Answer:
Answer: product of m and n will be 1.
Step-by-step explanation:
Answer:
option c
Step-by-step explanation:
<em>Step 1: Multiply each number in matrix A by -4</em>
( -4x-4 -4x-4 1x-4 )
( 1x-4 4x-4 7x-4)
( 2x-4 3x-4 3x-4)
( 16 16 -4 )
( -4 -16 -28)
( -8 -12 -12)
<em>Step 2: Multiply each number in matrix B by 8</em>
( 2x8 9x8 -9x8 )
( 8x8 8x8 -2x8 )
( 4x8 10x8 1x8 )
( 16 72 -72 )
( 64 64 -16 )
(32 80 8 )
<em>Step 3: Form the matrix of -4A + 8B by adding the correspondent numbers in the matrix.</em>
( 16+16 16+72 -4-72 )
( -4+64 -16+64 -28-16 )
( -8+32 -12+80 -12+8)
( 32 88 -76 )
( 60 48 -44)
( 24 68 -4 )
Therefore option c is correct.
!!
Refer to the diagram shown below.
BE = 2x² - x
DE = x² + 6
The intersecting diagonals bisect one another.
Therefore BE = DE, so that
2x² - x = x² + 6
x² - x - 6 = 0
Factorize.
(x + 2)(x - 3) = 0
x = -2, or x = 3.
When x = -2,
BE = 2(-2)² - (-2) = 10
DE = (-2)² + 6 = 10
Therefore BD = 20
When x = 3;
BE = 2(3²) - 3 = 15
DE = 3² + 6 = 15
Therefore BD = 30
Answer: Either 20 or 30.