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Ivan
4 years ago
6

When we looked at assigning the electrons in nitrogen to sites in the 2s and 2p orbitals, we used the 2s anti-bonding site. Whic

h statement about this site is not true?
A) This anti-bonding electron site has the second lowest energy level of all the sites in the 2s and 2p orbitals.
B) Although this site is not desirable for making a bond between atoms, it is a good site in the sense that the electrons can be close to the nucleus.
C)This site can accommodate a maximum of two electrons (i.e., one electron pair).
D) The energy level for this site is very similar to the energy level for the s 2s orbital site.

Chemistry
1 answer:
AveGali [126]4 years ago
6 0

Answer:

B) Although this site is not desirable for making a bond between atoms, it is a good site in the sense that the electrons can be close to the nucleus.  

Explanation:

An antibonding orbital points away from the nuclei, with a node between them, so the electrons are not held close to the nuclei. The orbital is not desirable for bonding.

The diagram below shows a σ*1s molecular orbital, but a σ*2s orbital has a similar shape.

A) is true. The σ*1s orbital has the lowest energy.

C) is true. Any orbital can accommodate at most one electron pair.

D) is may be true. Orbital energy decreases as atomic number increases, so the orbital energy of an N₂ σ*2s molecule may be close to that of a sulfur atom's 2s orbital.

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The picture to the right is the crystal of a
Sonbull [250]

Answer:

Circle Any 3 Red Spheres

Explanation:

All of these atoms are Carbon (C), as diamond is a network solid composed entirely of Carbon.  They are all the same.

4 0
3 years ago
How many g are equal to 345.7mg?
Mumz [18]

Answer:

0,3457 grams equal to 345.7mg

Explanation:

1000 mg-------1 g

345.7mg------x= (345.7mgx 1 g)/1000mg= <em>0,3457 g</em>

4 0
3 years ago
Read 2 more answers
How much time is needed to deposit 1.0 g of chromium metal from an aqueous solution of crcl3 using a current of 1.5 a?
PSYCHO15rus [73]
The metal component of the given compound, CrCl3, is chromium. The number of moles per 1 g of chromium is calculated through the equation below,

        n = (1 g Cr)(1 mol Cr/51.996 g Cr)
              n = 0.0192 mol Cr(3 electrons/1 mol Cr) 
                n = 0.0577 e-

Determine the number in charge by multiplying with Faraday's constant,

      C = (0.0577 mol Cr)((1 F/1 mol e-)(96485 C/ 1F)
             C = 5,566.87 C

Then, calculate time by dividing the charge with the current,

     t = 5566.87 C/1.5 A 
     t = 3711.25 minutes
     t = 61.84 hours

<span><em>Answer: 61.84 hours</em></span>


8 0
3 years ago
Read 2 more answers
Why must living things rely on thousands of catalysts for chemical reactions necessary for life?
Murrr4er [49]
Well, you don't need enzymes (biological catalysts) if you're willing to wait a century or two to digest a burger.

Without catalysts, complex reactions like digestion would take too long and the organism could not extract energy from the nutrients it eats in a practical time frame.

In addition, speed is everything in the biological world.

Some reactions and their speed relative to other organisms reactions determines who survives and who doesn't, among other aspects of life.

If a plant is slow to photosynthesize and grow in a habitat high in competition for sunlight real estate, other autotrophs will surely take over.
7 0
3 years ago
Read 2 more answers
Calculate the energy released in each of the following fusion reactions. Give your answers in MeV. (a) 2H + 3H → 4He + n 17.54 C
Vikentia [17]

Answer:

a) E = 17.55 MeV

b) E = 18.99 MeV

c) E = 3.29 MeV

d) You can use the methods applied for the other parts to solve this, the equation is not properly written

e) E = 4.075 MeV

Explanation:

Energy Released, E = \triangle M * 931.5

\triangle M = \sum M_{product} - \sum M_{reactant}

Mass of 1H, M_{H} = 1.007823

Mass of 2H, M_{2H} = 2.0141u

Mass of 3H, M_{3H} = 3.016 u

Mass of Helium, M_{4He} = 4.002602u

Mass of Beryllium, M_{7Be} = 7.01693 u

Mass of neutron, M_{n} = 1.008664 u

a) 2H + 3H \rightarrow 4He + n

\triangle M = (4M_{He} + M_{n} ) - (2M_{H} + 3 M_{H} )\\\triangle M = ( 4.0026 + 1.008664) - (2.0141 + 3.016 )\\\triangle M = -0.01884u

Energy released,

E = -0.01884 * 931.5\\E = -17.55 Mev

Energy released = 17.55 MeV

b) 4He + 4He \rightarrow 7Be + n

\triangle M = (M_{7Be} + M_{n} ) - (M_{4He} +  M_{4He} )\\\triangle M = ( 7.01693 + 1.008664) - (4.002602 + 4.002602 )\\\triangle M = 0.02039 u

Energy released,

E = 0.02039 * 931.5\\E = 18.99 Mev

c) 2H + 2H \rightarrow 3 He + n

\triangle M = (M_{3He} + M_{n} ) - (M_{2H} +  M_{2H} )\\\triangle M = ( 3.016 + 1.008664) - (2.0141 + 2.0141 )\\\triangle M = -0.003536 u

Energy released,

E = -0.003536 * 931.5\\E = -3.29 Mev

E = 3.29 MeV(Energy is released)

d) You can use the methods applied for the other parts to solve this, the equation is not properly written

e) 2H + 2H \rightarrow 3H + 1H

\triangle M = (M_{3H} + M_{1H} ) - (M_{2H} +  M_{2H} )\\\triangle M = ( 3.016 + 1.007825) - (2.0141 + 2.0141 )\\\triangle M = -0.00435 u

E = -0.00435 * 931.5\\E =-4.075 Mev

E = 4.075 MeV ( Energy is released)

5 0
3 years ago
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