Answer:
ur 2nd option would be the best
Answer:
3.2 moles
Explanation:
First, we'll begin by writing a balanced equation for the Combustion of methane to produce carbon dioxide. This is illustrated below:
CH4 + 2O2 —> CO2 + 2H2O
From the balanced equation above,
1 mole of methane (CH4) reacted to produced 1 mole of carbon dioxide (CO2).
Therefore, 3.2 moles of methane (CH4) will react to produce 3.2 moles of carbon dioxide (CO2).
From the illustration above, 3.2 moles of methane is needed to produce 3.2 moles of carbon dioxide.
Answer:
Molar mass of MgCl2 is 95 g/mol
Mg = 24 g/mol and Cl = 35.5 ×2 = 71 g/mol
moles = mass given/ molar mass
= 2.7/95 = 0.028 mol
volume = 250/1000 = 0.25 dm3 (ml is the same as dm3)
molarity of MgCl2 = moles/volume
= 0.028/0.25
= 0.112 mol/dm3
Answer/ explanation :
Protist can be multicellular or unicellular organisms
Plants are all multicellular and also exhibit cellular differentiation.
Protist can be autotroph, heterotrophic or decomposer
Plants are only autotrophs because they manufacture their own food through photosynthesis
Protists are microscopic, more diverse and abundant in nature
Plants are big and complex in nature
Nuclear DNA strands in plants are of higher complexity than those of protist
Plants require oxygen for cellular respiration process unlike protist which can be aerobic and some other species facultative anaerobic
Plants only can reproduce asexually through bulbs and tubers as in yam, potatoes while protists reproduce either sexually through meiosis or asexually through simple cell division.
Answer:
Repeated SN2 reactions occur leading to the formation of a racemic mixture
Explanation:
S-2-iodooctane is a chiral alkyl halide with an asymmetric carbon atom. The presence of an asymmetric carbon atom implies that it can rotate plane polarized light and thus lead to optical isomerism. The two configurations of the compound are R/S according to the Cahn-Prelong-Ingold system.
However, when S-2-iodooctane is treated with sodium iodide in acetone, repeated SN2 reactions occur since the iodide ion is both a good nucleophile and a good leaving group. Hence a racemic modification is formed in the system with time hence we end up with (±)- Iodooctane.
