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3 years ago

What multiplies to 1.25 and adds up to 3

Mathematics

1 answer:

Serggg [28]3 years ago

5 0

Answer:

2.5

Step-by-step explanation:

l x+y=3

ll x*y=1.25

l x=3-y

ll (3-y)*y =1.25

ll -y^2+3y-1.25=0

ll y^2-3y+1.25=0

a=1

b= -3

c=1.25

y1, 2 =(3+/-sqrt(9-4*1.25))/2

y1, 2 = (3+/-2)/2

y1=1.25 =>x=3-2.5=0.5

y2=0.5=> x=3-0.5=2.5

the numbers: o.5, 2.5

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Answer:

$S_{n} = \frac{2(4^{n}-1) }3} if r>1$

Step-by-step explanation:

Explanation:-

Geometric sequence:-

The geometric sequence is of the form

$a,ar,ar^{2},ar^{3}$ ……… be an infinite sequence

here first term is 'a' and ratio is 'r '

In this geometric sequence 'n' t h term is $t_{n} = a r^{n-1}$ ....(1)

Given data a1 term is '8 ' and ratio is '4'

substitute n=1 in equation(1)

$t_{1} = a r^{1-1}$ = 8

$ar=8$ ...........(2)

substitute r= 4 in equation(2)

now we get a(4)=8

dividing "4" on both sides , we get a = 2

Geometric series:-

$a+ar+ar^{2}+ar^{3}+$ .....is an infinite geometric series.

sum of this infinite series will be the upper limit of the fungal spores

that is we have to find sum of infinite series

$S_{n} = \frac{a(r^{n}-1) }{r-1} if r>1$

$S_{n} = \frac{2(4^{n}-1) }{4-1} if r>1$

$S_{n} = \frac{2(4^{n}-1) }3} if r>1$

Final answer:-

sum of this infinite series will be the upper limit of the fungal spores

$S_{n} = \frac{2(4^{n}-1) }3} if r>1$

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4 years ago

Which one does not belong 8 27 64 16

Brums [2.3K]

Answer:

27 doesn't belongs to this group

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