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Anon25 [30]
4 years ago
8

On a number line the directed line segment from Q to S has endpoints Q at -14 and S at 2. Point R partitions the directed line s

egment from Q to S in a 3:5 ratio.
Which expression correctly used the formula, to find the location of point R?
Mathematics
2 answers:
liq [111]4 years ago
8 0

Answer:

Step-by-step explanation:

The distance from Q to S is 2 - (-14), or 16.

We start at point Q.  Note how 3 and 5 add  up to 8, which allows us to write:

R = Q + (3/8)(16), or R = -14 + 6, or R = -8.

From R to S it is (5/8)(16), or 10 units.

The directed line segment is partitioned into segments of lengths 6 and 10, whose combined length is 16, as expected.

mars1129 [50]4 years ago
4 0

Answer:

14/5 or A

Step-by-step explanation:

I just took this assignment.

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Which is the factorization of 8x2 13x – 6? (8x – 3)(x 2) (x – 6)(8x 1) (2x – 2)(4x 3) (4x – 1)(2x 6)
vagabundo [1.1K]

we have

8x^2+13x - 6

Equate the function to zero

8x^2+13x - 6=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

8x^2+13x = 6

Factor the leading coefficient

8(x^2+\frac{13}{8}x) = 6

Complete the square. Remember to balance the equation by adding the same constants to each side.

8(x^2+\frac{13}{8}x) = 6

8(x^2+\frac{13}{8}x+\frac{169}{256}) = 6 +\frac{169}{32} \\ \\ 8(x+\frac{13}{16} )^{2} =\frac{361}{32} \\ \\ (x+\frac{13}{16} )^{2} =\frac{361}{256}\\ \\ (x+\frac{13}{16} ) =(+/-)\sqrt{\frac{361}{256}} \\ \\ (x+\frac{13}{16} ) =(+/-)\frac{19}{16}  \\ \\ x1=-\frac{13}{16} +\frac{19}{16} =\frac{6}{16}\\ \\ x2=-\frac{13}{16} -\frac{19}{16}=-2

the factorization is equal to

8*(x-\frac{6}{16} )*(x+2)=(8x-3)*(x+2)

therefore

<u>the answer is</u>

(8x-3)*(x+2)




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