There are 156 rows of trees altogether.
<u>Step-by-step explanation:</u>
Given that for every 11 rows of Red delicious , they plant 3 rows of Royal Gala.
Thus for 1 row of Royal Gala there would be 11/3 rows of Red delicious.
Number of rows of Royal Gala=18
For 11 rows of red delicious,they plant 7 rows of yellow delicious.
Thus for 1 row of Red delicious,there would be 7/11 rows of yellow delicious.
For 66 rows of red delicious there would be
For 11 rows of red delicious,they plant 5 rows of Braeburn
for 1 row of red delicious,they would plant 5/11 rows of Braeburn.
For 11 rows of red delicious,they would plant
Total rows of trees=66+42+30+18=156
Answer:
-4 =x
Step-by-step explanation:
5x+8=3x
Subtract 5x from each side
5x-5x+8=3x-5x
8 = -2x
Divide by -2
8/-2 = -2x/-2
-4 =x
Let <em>a</em> and <em>b</em> be the two numbers. Then
<em>a</em> + <em>b</em> = -4
<em>a b</em> = -2
Solve the second equation for <em>b</em> :
<em>b</em> = -2/<em>a</em>
Substitute this into the first equation:
<em>a</em> - 2/<em>a</em> = -4
Multiply both sides by <em>a</em> :
<em>a</em>² - 2 = -4<em>a</em>
Move 4<em>a</em> to the left side:
<em>a</em>² + 4<em>a</em> - 2 = 0
Use the quadratic formula to solve for <em>a</em> :
<em>a</em> = (-4 ± √(4² - 4(-2))) / 2
<em>a</em> = -2 ± √6
If <em>a</em> = -2 + √6, then
-2 + √6 + <em>b</em> = -4
<em>b</em> = -2 - √6
In the other case, we end up with the same numbers, but <em>a</em> and <em>b</em> are swapped.
The answer to this would be 4(w-4)
