There are 5 solutions for this system.
x^2 + 4y^2 = 100 ____1
4y - x^2 = -20 ____2
Add both 1 & 2 together. x^2 gets cancelled
4y^2 + 4y = 80 (send 80 to the other side and divide by 4)
Then equation the becomes : y^2 + y -20 =0
Now factorise the equation: (y+5) (y-4) = 0
Solve for y : y = -5 and y = 4
Using the values of y to find the values of x. From equation 1:
x^2 = 100 - 4y^2 x = /100 - 4y^2 (/ means square root) Replace values of y
y = -5, x = /100 - 4(-5)^2 = /100 - 100 = 0
y = 4, x = /100 - 4(4)^2 = / 100 - 64 = /36 = -6 or 6
Thus we have 6 solutions y = -5, 4 and x = -6, 0, 6
Answer:
The most reasonable answer would likely be the first.
"When a pair of parallel lines is intersected by a third line, the alternate exterior angles are congruent."
Step-by-step explanation:
Answer:
perpendicular
Step-by-step explanation:
start but putting each line into the standard line format
2x-y=-5
-y=-2x-5
y=2x+5
x+2y=-6
2y=-x-6
y=-(1/2)x-3
if lines are parallel the slopes would be the same. 2 is not equal to -1/2
if lines are perpendicular the slope of one would be the opposite inverse of the other.
negative inverse of 2 = - (1/2)
so the lines are perpendicular
Cot x= cosx/sinx =√3
tan x= 1/ √3
cos x = √2 /2
x= 45
tan45= 1
tan x= -4/3
csc x= 13/5
1/sin x = 13/5
sin x= 5/13
x=22.62
tan x= 5/12
the 24th term of the arithmetic is 146
