What is 3-(-7)+11-(9)

How do you think this property might extend to multiplication and division of functions

NNADVOKAT [17]

You have to give a question

8 0

3 years ago

Is 3x-15=2(x-5)+x always true or never true

In-s [12.5K]

I’m not sure what you mean. But if you are talking about, 3x-15=2 the answer would not be x-5 it would be x= 17/3. So that means your answer would be not true. If I’m explaining the wrong thing comment and lmk :) !

7 0

2 years ago

Answer fast PLS asap TY

IgorLugansk [536]

Answer:

<h2>56.52 units²</h2>

Step-by-step explanation:

Given, Radius ( r ) = 6 units

Area of semi-circle = ?

Now, let's find the area of semi-circle:

$\frac{1}{2} \pi \: {r}^{2}$

plug the values

$= \frac{1}{2} \times 3.14 \times {6}^{2}$

Evaluate the power

$= \frac{1}{2} \times 3.14 \times 36$

Calculate

$= 56.52 \:$ units²

hope this helps...

Best regards!!

7 0

3 years ago

Read 2 more answers

Solve one, any question you want, please show work,

luda_lava [24]

Answer:

Step 1: Variables are q for quarters and d for dimes. So d = dimes and q = quarters

Step 2: The two equations that form a system of equations are:

$\left \{ {{0.1d+.25q=3.70} \atop {d+q=19}} \right.$

Step 3: Work is shown on the attachment and on the step-by-step explanation

Step 4: Given the context of the problem, the solution of the amount of dimes and quarters, which is 7 dimes and 12 quarters, is needed to satisfy both systems to concur that there was 7 dimes and 12 quarters in a sum of money that amounted to $3.70 with 19 coins in total.

Step-by-step explanation:

Step 1: To first attempt to solve this, we must have to set up two variables for the amount of value a quarter and a dime has. So since a quarter is worth 0.25¢ in and a dime is worth 0.10¢, then we can set up one of the equations to be:

$0.1d + .25q = 3.70$

And we set it to equal the $3.70 because that's the amount that the sum of money totals to.

Step 2: Now to get the other side of the equation, we use the variables again, d and q and set that to equal 19 because that is the amount of coins that there is in total.

Step 3: Now that we have both equations, we can solve the problem now.

$\left \{ {{0.1d+.25q=3.70} \atop {d+q=19}} \right.$

Let's first solve this equation by setting one of the side's variables the same absolute value, but not the same integer value so that we can cross it off. I will choose the equation $d+q=19$ to be multiplied by -.1 so that we can cross off both 0.1d and -0.1d after the result of the multiplication:

$\left \{ {{0.1d+.25q=3.70} \atop {-.1d+-.1q=-1.9}} \right.$

Now, lets cross off everything that we can, and add up the variables together. This includes adding .25q + (-.1q) and adding 3.70 + -1.9.

Now we have:

$\left \{ {{.25q=3.70} \atop {-.1q=-1.9}} \right.$

Now, what we do from here is add the left side and the right side side to get one equation, which is:

$.15q=1.8$

Finally, we divide both sides to get q=12, which means that there are 12 quarters. Since there are 19 coins in total, we can subtract 12 from 9 to get the remaining amount of dimes, which is 7.

In conclusion, q=12 and d=7.

My written work is also provided in the attachment!!!

Step 4: What does this mean in the context of the question?

This basically means that the solution of the amount of dimes and quarters, which is 7 dimes and 12 quarters, is needed to satisfy both systems to concur that there was 7 dimes and 12 quarters in a sum of money that amounted to $3.70 with 19 coins in total.

In simpler terms, this means that we need 7 dimes and 12 quarters to satisfy that there was a sum of money that amounted to $3.70 with 19 coins in total .