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BARSIC [14]
4 years ago
10

What’s the answer to this equation : HELP ASAP

Mathematics
1 answer:
RSB [31]4 years ago
7 0
2/3 x - 1/5 x = x - 1

Change the fractions to have the same denominators:

10/15 x - 3/15 x = 15/15 x - 1

Simplify the left side of the equation:

7/15 x = 15/15x - 1

Get everything to the right side of the equation:

0 = 8/15 x - 1

Move the (1) to the left side:

1 = 8/15x

Multiply 15 to both sides:

15 = 8x

Divide both sides by 8

15/8 = x

Answer is x=8/15
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Find (-3/7) divided (-1 1/14)
Andrews [41]

Answer:

2/5

Step-by-step explanation:

first, we convert the mixed fractions to improper fractions,

-1\frac{1}{14}=\frac{15}{14}

so then we find what -\frac{3}{7}\div-\frac{15}{14}

-\frac{3}{7}\div-\frac{15}{14} = -\frac{3}{7} * -\frac{14}{15}

and that equals \frac{3*14}{7*15} , which equals \frac{42}{105}. We can simplify that to 2/5

3 0
3 years ago
On a coordinate plane, 3 triangles are shown. Triangle B C D has points (1, 4), (1, 2), (5, 3). Triangle B prime C prime D prime
Tresset [83]

The rule which describe the composition of transformations that

maps ΔBCD to ΔB"C"D" is:

Reflection across the y-axis composition translation of 6 units x,

negative 5 units y ⇒ last answer

Step-by-step explanation:

Let us revise the reflection across the y-axis , horizontal translation

and vertical translation

1. If point (x , y) is reflected across the y-axis, then its image is (-x , y)

2. If point (x , y) is translated h units to the right, then its image is

   (x + h , y), if translated h units to the left, then its image is (x - h , y)

3. If point (x , y) is translated k units up, then its image is (x , y + k),

   if translated k units down, then its image is (x , y - k)

∵ The vertices of triangle BCD are (1 , 4) , (1 , 2) , (5 , 3)

∵ The vertices of triangle B'C'D' are (-1 , 4) , (-1 , 2) , (-5 , 3)

∵ The x-coordinates of the vertices of Δ B'C'D' have the same

   magnitude of x-coordinates of Δ BCD and opposite signs

∴ Δ B'C'D' is the image of Δ ABC after reflection across the y-axis

∵ The vertices of triangle B'C'D' are (-1 , 4) , (-1 , 2) , (-5 , 3)

∵ The vertices of triangle B''C''D'' are (5 , -1) , (5 , -3) , (1 , -2)

∵ The image of -1 is 5 and the image of -5 is 1

∴ The x-coordinates of the vertices of triangle B'C'D' are added by 6

∵ The image of 4 is -1 , image of 2 is -3 and the image of 3 is -2

∴ The y-coordinates of the vertices of triangle B'C'D' are subtracted

   by 5

∴ Δ B"C"D" is the image of Δ B'C'D' by translate 6 units to the right

  and 5 units down ⇒ (x + 6 , y - 5)

The rule which describe the composition of transformations that

maps ΔBCD to ΔB"C"D" is:

Reflection across the y-axis composition translation of 6 units x,

negative 5 units y

Learn more:

You can learn more about reflection in brainly.com/question/11203617

#LearnwithBrainly

3 0
3 years ago
Read 2 more answers
If f(x) = 1 – x2 + x3, then f(-1) =
Monica [59]

Answer:

Step-by-step explanation:

f(-1)= 1 - (-1)^2 + (-1)^3 = 1 - 1 - 1 = 0 - 1 = -1

4 0
3 years ago
A food safety guideline is that the mercury in fish should be below 1 part per million​ (ppm). Listed below are the amounts of m
nignag [31]

Answer:

Confidence Interval: (0.44,1.00)

Step-by-step explanation:

We are given the following data set:

0.60, 0.74, 0.09, 0.89, 1.31, 0.51, 0.94

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{:5.08}{7} = 0.725

Sum of squares of differences = 0.8809

S.D = \sqrt{\frac{0.8809}{6}} = 0.383

90% Confidence interval:  

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 6 and}~\alpha_{0.10} = \pm 1.943  

0.725 \pm 1.943(\frac{0.383}{\sqrt{7}} ) =0.725 \pm 0.2812 = (0.44,1.00)

No, it does not appear that there is too much mercury in tuna​ sushi.

5 0
4 years ago
The cost, in dollars, of parking a car in a busy downtown area for h hours is $20 + $2h.
MAVERICK [17]

Answer:

y= 20h + 2

   its $20 times the hours for every 2 hours

7 0
3 years ago
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