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Daniel [21]
3 years ago
11

What is the solution to the quadratic equation 8m^2+7m-15=-7 ?

Mathematics
1 answer:
Aleks04 [339]3 years ago
4 0
Make equal to zero
add7 both sides
8m^2+7m-8=0
quadratic fomrula

if you have
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}

8m^2+7m-8=0
a=8
b=7
c=-8

x=\frac{-7+/- \sqrt{7^{2}-4(8)(-8)} }{2(8)}
x=\frac{-7+/- \sqrt{49+256} }{16}
x=\frac{-7+/- \sqrt{305} }{16}

x=\frac{-7+ \sqrt{305} }{16} or x=\frac{-7- \sqrt{305} }{16}

aprox
x=-1.52902 or 0.654016


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