What is the solution to the quadratic equation 8m^2+7m-15=-7 ?

1 answer:

4 0

Make equal to zero
add7 both sides
8m^2+7m-8=0
quadratic fomrula

if you have
ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$

8m^2+7m-8=0
a=8
b=7
c=-8

x= $\frac{-7+/- \sqrt{7^{2}-4(8)(-8)} }{2(8)}$
x= $\frac{-7+/- \sqrt{49+256} }{16}$
x= $\frac{-7+/- \sqrt{305} }{16}$

x= $\frac{-7+ \sqrt{305} }{16}$ or x= $\frac{-7- \sqrt{305} }{16}$

aprox
x=-1.52902 or 0.654016

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Joyce rented a booth at a carnival at a cost of $95 to sell handmade beaded necklaces. The cost of making and packaging each bea

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Answer:

To make a profit of at least $500 she must sell at least 12 necklaces

Step-by-step explanation:

Joyce rented a booth at a carnival at a cost of $95 to sell handmade beaded necklaces. The cost of making and packaging each beaded necklace was $15. If Joyce sells the beaded necklaces at $35 each then we have to find beaded necklaces she sell to make a profit of at least $500.

The costs side of the equation, we have:

Let no. of necklaces that she sell are x

∴ The cost of making and packaging x beaded necklace is $15x

Total Cost = 95+15x

Now, Joyce sells the beaded necklaces at $35 each. Therefore, selling price will be $35x

To make a profit of at least $500 the equation can be written as

$95+15x+500\leq35x$