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docker41 [41]
3 years ago
7

What is 8.239 round to the tenths place

Mathematics
1 answer:
Karolina [17]3 years ago
5 0
8.2
3 does not add 1 to 2 so it's 8.2
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2 years ago
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Find the ninth term of the sequence sqrt 5, sqrt 10, ^2sqrt 5
hjlf
The rule of geometric sequence is   ⇒⇒⇒ a * r^(n-1)
Where a is the first term and  r is the common ratio
for the given sequence  √5 , √10 , 2√5 , .......
a = √5
r = √10 / √5 = √2
The ninth term = √5 * (√2)^(9-1) = √5 * (√2)⁸ = 16 √5

the correct answer is the third option 16√5
5 0
3 years ago
Solve the simultaneous equations<br> -x + 5y = -7<br> x + y = – 5<br> x = 1<br> y= 0
vodomira [7]

y= -5-x

-x + 5(-5-x) = -7

-x -25-5x =-7

-x-5x = 25 -7

-6x= 18

x = -3

-3 +y = -5

y= -5 +3

=-2

-(-3) + 5(-2)

3 - 10 = -7

5 0
2 years ago
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Some students were asked what kinds of animals they have at home.
Nataly_w [17]

(a) Animals by popularity; Dogs, Cats, Others, Horses.

(b) If 250 students were interviewed, 20 students have other pets.

(c) No, it was incorrect.

Step-by-step explanation:

Step 1; We arrange the different pets in chronological order, from the highest percent to the lowest percent;

1. Dogs - 67%,

2. Cats - 20%

3. Others - 8%,

4. Horses - 1%.

None is not included in this list.

Step 2; If 250 students were interviewed, 8% of those have other pets. So we need to calculate how much 8% of 250 is.

8% of 250 = \frac{8}{100} × 250 = 0.08 × 250 = 20.

So 20 students had other pets.

Step 3; 20% of the interviewed students had cats. If 75 students had cats, we need to equate 20% to the 75 and find out how many students were actually interviewed.

20% × x = 75, 0.2 × x = 75,

x = \frac{75}{0.2} = 375.

So if 375 students were interviewed, 75 students would have cats. So the estimate of 250 students being interviewed is incorrect.

8 0
3 years ago
If h (x) = {(-2,3), (0,4), (1,6), (2, 9)}<br><br> then what set of values represent h-1 (x) ?
vfiekz [6]

Answer:

h^{-1}(x)=\{(3,-2),(4,0),(6,1),(9,2)\}

Step-by-step explanation:

Given: h(x)=\{(-2,3),(0,4),(1,6),(2,9)\}

To find: h^{-1}(x)

Solution:

A relation is said to be a function if each and every element of the domain has a unique image in the co-domain.

Inverse of a function exist if it is both one to one and onto.

h(x)=\{(-2,3),(0,4),(1,6),(2,9)\}

h^{-1}(x)=\{(3,-2),(4,0),(6,1),(9,2)\}

7 0
2 years ago
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