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2 years ago

Can you help me with this, please?

Mathematics

1 answer:

Aloiza [94]2 years ago

3 0

Answer:

y =x-12

Step-by-step explanation:

$(x_1, y_1) = (16, 4) \ \ \ and \ \ \ (x_2, y_2) = (17, 5)$

Equation of straight line is

$y-y_1 =\frac{y_2-y_1}{x_2-x_1} (x-x_1)$

$y-4 =\frac{5-4}{17-16} (x-16)$

$y =(x-16)+4$

$y =x-12$

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New equation: -4y+8=12

Now you solve like a normal equation
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New equation: -4y=4

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Can you help me with this, please? ​

Can you help me with this, please?