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3 years ago

If a cylinder holds a volume of 100 cm3, and is 30 cm tall, which is the area of the bottom of the cylinder

Physics

2 answers:

PSYCHO15rus [73]3 years ago

6 0

3.33cm squared
Hope this helped

RUDIKE [14]3 years ago

6 0

V=h*Bottom

100=30*Bottom
30*Bottom=100
Bottom=100/30
Bottom= 3,3cm^2

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Given,

mass of the smaller disk = $M_1\ =\ 0.900\ kg$
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A block of mass m is hanging on the smaller disk,

From the f.b.d. of the block,

Let 'a' be the acceleration of the block and 'T' be the tension in the string.

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$\therefore \tau\ =\ I\alpha\\\Rightarrow TR_1\ =\ \dfrac{Ia}{R_1}\\\Rightarrow T\ =\ \dfrac{Ia}{R_1^2}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,enq (2)$

From eqn (1) and (2), we get,

$mg\ -\ ma\ =\ \dfrac{Ia}{R_1^2}\\\Rightarrow a\ =\ \dfrac{mg}{\dfrac{I}{R_1^2}\ +\ m}\\\Rightarrow a\ =\ \dfrac{1.60\times 9.81}{\dfrac{2.27\times 10^{-3}}{0.027^2}\ +\ 1.60}\\\Rightarrow a\ =\ 2.91\ m/s^2$

part (b)

In this case the mass is rapped on the larger disk,

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Let ' $a_2$ ' be the acceleration of the block in the second case,

From the above expression,

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3 years ago