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artcher [175]
3 years ago
13

Estimate the amount of work performed on a 1200 kg car as it accelerates at 1.2 m/s2 over a 150 meter distance. How fast will th

e car be moving at the end if it started from rest?

Physics
1 answer:
spayn [35]3 years ago
5 0

Answer:

W= 2.16 x 10^5 K,  Vf = 18.97 m/s

Explanation:

Solution is attached.

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5) A person holds a 1.7 kg bucket and lets it move down at
Elena L [17]

Answer:

12.5J

Explanation:

Given parameters:

Mass of bucket  = 1.7kg

Height  = 75cm  = 0.75m

Unknown;

Work done on the bucket by the person  = ?

Solution:

To solve this problem, we use the work done equation;

  Work done  = force x distance  = mgh

 m is the mass  

  g is the acceleration due to gravity

  h is the height

Now, insert parameters and solve ;

     Work done  = 1.7 x 9.8 x 0.75  = 12.5J

7 0
3 years ago
Water flows through a first pipe of diameter 3 inches. If it is desired to use another pipe for the same flow rate such that the
Alborosie

Answer:

the diameter of the second pipe is 2.52 in

Explanation:  

Given the data in the question;

We know that; the rate of flow is the same;

so

Av1 = Av2

v ∝ √h

\frac{A1}{A2} = \frac{V2}{V1}

\frac{A1}{A2}  = √(  \frac{h2}{h1} )

( π/4.D1² / π/4.D2² ) = √(  \frac{h2}{h1} )

( D1² / D2² ) =  √(  \frac{2h1}{h1} ) since second is double of first

so

( D1² / D2² ) =  √(  \frac{2}{1} )  

3² / D2² =  √2

D2²√2  = 9

D2² = 9/√2

D2² = 9 / 1.4142

D2² = 6.364

D2 = √ 6.364

D2 = 2.52 in

Therefore, the diameter of the second pipe is 2.52 in

3 0
3 years ago
What is the tendency of a material to oppose the flow of charge?
elena55 [62]

I think the answer is Resistance.  If the link i posted int he comment is right.

8 0
4 years ago
The current in a wire is 4.00A. How much time is needed for 1 mole of electrons (6.02×1023 electrons) to pass a point in the wir
scZoUnD [109]

Answer:

t= 24080 s

Explanation:

Given that

Current in the wire ,I = 4 A

The charge ,q = 6.02 x 10²³ e C

We know that

I=\dfrac{q}{t}

I=Current  

q=Charge

t=time

t=\dfrac{q}{I}

Now by putting the values in the above equation we get'

t=\dfrac{6.02\times 10^{23}\times 1.6\times 10^{-19}}{4}\ s

t= 24080 s

8 0
3 years ago
A man walks 400 m in the direction 45° north of east. Represent this vector graphically by
Marrrta [24]

Answer:

Explanation:

Coordinate system is one that describe the location of an object in a given plane. It implies the use of axes (coordinates) and points.

Given that the man in the question walks 400 m due north of east. The cardinal points can be used in this case, with the north and east cardinals as the required axis.

scale = \frac{length on drawing}{original length}

         = \frac{10}{400}

         = \frac{1}{40}

scale = 1:40

This is a reduced scale which implies that 1 cm on the drawing is equal to 40 m on the original length.

The man's direction is 45^{o} north of east.

The graphical drawing of the vector is herewith attached to this answer.

5 0
3 years ago
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