a skater increases her speed uniformly from 2.0 m/s to 10 m/s in 3.0s. what is the acceleratioon of the biker?

Physics

1 answer:

sergey [27]4 years ago

5 0

Answer:

a= 2.667 m/s²

Explanation:

Given that

Initial velocity ,u= 2 m/s

Final velocity ,v= 10 m/s

Time taken ,t= 3 s

As we know that

v = u + at

a=Acceleration ,u=Initial velocity ,v= Final velocity ,t=time

Now by putting the values in the above equation

v = u + at

10 = 2 + a x 3

8 = 3 a

$a=\dfrac{8}{3}\ m/s^2$

a= 2.667 m/s²

Therefore the acceleration of the biker will be 2.667 m/s²

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