Answer:
k=320N/m
Explanation:
Step one:
given data
Let the initial/equilibrum position be x
mass m1= 0.2kg
F1= 0.2*10= 2N
elongation e= 9.5cm= 0.095m
mass m2=1kg
F2=1*10= 10N
elongation e= 12cm= 0.12m
Step two:
From Hooke's law, which states that provided the elastic limits of a material is not exceeded the extention e is proportional to applied Force F
F=ke
2=k(0.095-a)
2=0.095k-ka----------1
10=k(0.12-a)
10=0.12k-ka----------2
solving equation 1 and 2 simultaneously
10=0.12k-ka----------2
- 2=0.095k-ka----------1
8=0.025k-0
divide both side by 0.025
k=8/0.025
k=320N/m
Answer:
A. Kinetic energy is converted to electric potential energy, and the proton moves more slowly.
Explanation:
When a moving proton is brought close to a stationary one, the kinetic energy of the moving one is converted to electric potential and the proton moves more slowly.
Kinetic energy is the energy due to the motion of a body. A moving proton will possess this form of energy.
Two protons according to coulombs law will repel each other with an electrostatic force because they both have similar charges. This will increase their electric potential energy of both of them.
Potential energy is the energy at rest of a body. As it increases, the motion of a body will be slower and it will tend towards being stationary.
Answer:
C. 0 J
Explanation:
When an object moves in a circle, friction provides the centripetal force. Hence, it is acting towards the centre of the circle. The displacement of the object is tangential to the circle at the point of interest. Hence, the angle between the frictional force and the displacement is 90°.
Work done is given by
<em>W</em> = <em>Fd</em> cos <em>θ</em>
where <em>F</em> is the force, <em>d</em> is the displacement and <em>θ</em> is the angle between them.
<em>W</em> = <em>Fd</em> cos 90° = 0 J
Hence, the work done by friction is 0 J.
<span>F = m*a = 7000kg * 9.8N/kg = 68,600 N.
68,600 N is your answer
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Answer:
The steam will start to condense at 6.6 mm into the pipe
Explanation:
The volume flow rate =π×(50/1000)²/4×10 = 0.0196 m³/s
The specific volume of the steam = 1.769 m³/kg
Therefore;
The mass flow rate = 0.0196/1.769 = 0.011099 kg/s
The resistance of the insulation material = ln(0.075/0.05)/(2×π×0.075) = 0.860 K/W
The resistance of the outside film of the insulator = 1/(15×2×π×0.075×1) = 0.14147 K/W
The total resistance = 0.14147 + 0.860 = 1.00147 K/W
1/(UA) = 1.00147 K/W
A = 2×π×0.05×1
1/U = 0.3146
U = 3.178 W/m² K
We have;
T(x) = T₀ + (Tin - T₀) exp(-UπDx/mcp)
Therefore, when T(x) = 100°C, we have;
100 = 20 + (120 - 20)exp(-3.178×π×0.05x/(0.011099 × 1.33))
Solving, we get
x = 6.597× 10⁻³ m ≈ 6.6 mm
Therefore, the steam will start to condense at 10 mm into the pipe.
