Answer:
The length of the rectangle is 13 inches and its width (13 + 12) is 25 inches.
Step-by-step explanation:
You have to consider the formula of the perimeter = 2·length + 2·width.
If we call "x" to the length ⇒ width = x + 12 .
Perimeter = 2x + 2·(x + 12) ⇒ Perimeter = 2x + 2x + 24
⇒Perimeter = 4x + 24. ⇒ 76 = 4x + 24 ⇒ 76 - 24 = 4x ⇒52 = 4x
⇒ 52/4 = x ⇒ x = 13.
So, the length of the rectangle is 13 inches and its width (13 + 12) is 25 inches.
Answer:
width = 2 units
Step-by-step explanation:
If the length of a rectangle is (x) units, then that means that the width of a rectangle is x - 4 units.
the area of a rectangle is length * width
so just substitute the values that we have now.
x (length) * (x-4) width = 12 (area of rectangle)
so that gives us
x^2 - 4x =12
subtract 12 from both sides
x^2 - 4x - 12 =0
now factor this equation
x^2 + 2x - 6x -12 = 0
x(x+2) - 6(x+2) = 0
(x-6)(x+2) = 0
x = 6, or x = -2 REMEMBER THAT VALUE OF x = LENGTH, IT CANNOT BE NEGATIVE AS YOU CANT HAVE NEGATIVE VALUE OF A SIDE
length = 6, and width = 6 -4 = 2
The answers are:
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[B]: "√12 " ; AND:
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[D]: "<span>√20" .
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Note: "Irrational numbers" have decimals that are: 1) non-terminating; AND: 2) non-repeating.
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Consider the answer choices given; and consider the given information that there "should be no more than one answer.
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Consider the following answer choices:
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Choice A) "</span><span>√9" = 3 . Rule out this choice.
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Choice C) "</span><span>√16" = 4 . Rule out this choice.
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Choice E) "</span><span>√25" = 5. Rule out this choice.
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We are left with 2 (two) remaining answer choices:
[B]: "</span>√12" ; and: [D]: "<span>√20" .
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If there are more than one answer, then these two choices should be the correct answer. However, let us explore these two choices, using a calculator.
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[B]: </span>"√12" = 3.4641016151377546
[D]: "√20" = 4.4721359549995794
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These two answer choices should the correct answers.
Answer:
<h3>A≈974.83</h3><h3>V Volume </h3><h3>2862</h3><h3>
Step-by-step explanation:</h3>
<h3>Using the formulas</h3><h3>A=4πr2</h3><h3>V=4</h3><h3>3πr3</h3><h3>Solving forA</h3><h3>A=π⅓(6V)⅔=π⅓·(6·2862)⅔≈974.83372</h3>
<h3>brainliest pls and ur welcome</h3>
For number 2. The pilot flew 4 circuits and in total by the 5th day he flew 14 right?
