Answer:
598 books
Step-by-step explanation:
Let x be the number of books in the 3rd pile. We will have then:
1st pile: 2x + 10
2nd pile: 2x
3rd pile: x
3000 = (2x + 10) + (2x) + (x)
3000 = 5x + 10
3000 - 10 = 5x
2990 = 5x
2990/5 = x
x = 598 books in the third pile!
We can check that:
3000 = 2*598 + 10 + 2*598 + 598
3000 = 1196 + 10 + 1196 + 598
3000 = 3000 CHECK!
P(<100) = P((new or change) & <100) = P(new & <100) + P(change & <100)
... = P(<100 | new)*P(new) + P(<100 | change)*P(change)
... = 0.90*0.70 + 0.20*0.30
... = 0.63 + 0.06 = 0.69 . . . . probability of completing a transaction in < 100 ms
12subtract4
12-4
they want me to write more then 20 charaters
Answer:
m-1
Step-by-step explanation:
