The probability that at least 2 of the dinners selected are pasta dinners will be 0.8181...
<u><em>Explanation</em></u>
Pasta dinners = 7 , Chicken dinners = 6 and Seafood dinners = 2
The student selects 5 of the total 15 dinners. So, total possible ways for selecting 5 dinners 
For selecting at least 2 of them as pasta dinners, the student can select 2, 3, 4 and 5 pasta dinners from total 7 pasta dinners.
So, the possible ways for selecting 2 pasta dinners 
The possible ways for selecting 3 pasta dinners 
The possible ways for selecting 4 pasta dinners 
The possible ways for selecting 5 pasta dinners 
Thus, the probability for selecting at least 2 pasta dinners 
Answer:
the answer will stay the same
Answer:
1.6
Step-by-step explanation:
I used an arc length calculator
Answer: 250%
since, 100% = 100/100
250% = 250/100
Step-by-step explanation:
Answer:
<NBE = 120°
Step-by-step explanation:
From the above attachment,
<KMB = 30°
<KBT = 90° (perpendicular angles are equal to 90°)
<MBE = x
<KMB + <KBT + <MBE = 180° (angles on a straight line are equal to 180°)
30° + 90° + <MBE = 180°
120° + <MBE = 180°
Solve for <MBE
<MBE = 180° - 120°
<MBE = 60°
<MBE = <TBN (vertical angles are congruent, making them equal to each other).
<TBN = 60°
<TBN + <NBE = 180° (angles on a straight line are equal to 180°)
60° + <NBE = 180°
<NBE = 180° - 60°
<NBE = 120°
Angle <NBE is equal to 120°
