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slava [35]
3 years ago
13

He point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = y minus 1 equals StartFracti

on one-fourth EndFraction left-parenthesis x minus 12 right-parenthesis.(x – 12). What is the standard form of the equation for this line?
x – 4y = 8
x – 4y = 2
4x – y = 8
4x – y = 2
Mathematics
2 answers:
ruslelena [56]3 years ago
8 0

Answer:

x-4y=8

Step-by-step explanation:

we have

y-1=\frac{1}{4}(x-12)

Convert to standard form

Ax+By=C

where

A is a positive integer

B and C are integers

Multiply by 4 both sides to remove the fraction

4y-4=x-12

subtract 4y both sides

-4=x-12-4y

Adds 12 both sides

-4+12=x-4y

8=x-4y

Rewrite

x-4y=8

Maslowich3 years ago
7 0

Answer:

a

Step-by-step explanation:

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