Question

He point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = y minus 1 equals StartFraction one-fourth EndFraction left-parenthesis x minus 12 right-parenthesis.(x – 12). What is the standard form of the equation for this line?
x – 4y = 8
x – 4y = 2
4x – y = 8
4x – y = 2

Answer 1

Answer:

$x-4y=8$

Step-by-step explanation:

we have

$y-1=\frac{1}{4}(x-12)$

Convert to standard form

$Ax+By=C$

where

A is a positive integer

B and C are integers

Multiply by 4 both sides to remove the fraction

$4y-4=x-12$

subtract 4y both sides

$-4=x-12-4y$

Adds 12 both sides

$-4+12=x-4y$

$8=x-4y$

Rewrite

$x-4y=8$

Answer 2

Answer:

a

Step-by-step explanation: