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2 years ago

Pls answer this work sheet

Mathematics

1 answer:

Troyanec [42]2 years ago

8 0

Answer:

It is not letting me to download!!!

Step-by-step explanation:

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Ben and Josh went to the roof of their 40-foot tall high school to throw their math books offthe edge.The initial velocity of Be

Taya2010 [7]

Answer

Josh's textbook reached the ground first

Josh's textbook reached the ground first by a difference of $t=0.6482$

Step-by-step explanation:

Before we proceed let us re write correctly the height equation which in correct form reads:

$h(t)=-16t^2 +v_{o}t+s$ Eqn(1).

Where:

$h(t)$ : is the height range as a function of time

$v_{o}$ : is the initial velocity

$s$ : is the initial heightin feet and is given as 40 feet, thus Eqn(1). becomes:

$h(t)=-16t^2 + v_{o}t + 40$ Eqn(2).

Now let us use the given information and set up our equations for Ben and Josh.

Ben:

We know that $v_{o}=60ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+60t+40$ Eqn.(3)

Josh:

We know that $v_{o}=48ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+48t+40$ Eqn. (4).

Now since we want to find whose textbook reaches the ground first and by how many seconds we need to solve each equation (i.e. Eqns. (3) and (4)) at $h(t)=0$ . Now since both are quadratic equations we will solve one showing the full method which can be repeated for the other one.

Thus we have for Ben, Eqn. (3) gives:

$h(t)=0-16t^2+60t+40=0$

Using the quadratic expression to find the roots of the quadratic we have:

$t_{1,2}=\frac{-b+/-\sqrt{b^2-4ac} }{2a} \\t_{1,2}=\frac{-60+/-\sqrt{60^2-4(-16)(40)} }{2(-16)} \\t_{1,2}=\frac{-60+/-\sqrt{6160} }{-32} \\t_{1,2}=\frac{15+/-\sqrt{385} }{8}\\\\t_{1}=4.3276 sec\\t_{2}=-0.5776 sec$

Since time can only be positive we reject the $t_{2}$ solution and we keep that Ben's book took $t=4.3276$ seconds to reach the ground.

Similarly solving for Josh we obtain

$t_{1}=3.6794sec\\t_{2}=-0.6794sec$

Thus again we reject the negative and keep the positive solution, so Josh's book took $t=3.6794$ seconds to reach the ground.

Then we can find the difference between Ben and Josh times as

$t_{Ben}-t_{Josh}= 4.3276 - 3.6794 = 0.6482$

So to answer the original question:

Whose textbook reaches the ground first and by how many seconds?

Josh's textbook reached the ground first
Josh's textbook reached the ground first by a difference of $t=0.6482$

3 0

3 years ago

Please help me!! 2(5 – x)^4/3 -11 =151

larisa [96]

Answer:

$-\frac{\left(-x+5\right)^4}{4}\\$

7 0

3 years ago

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James took a math quiz in which he earned 1 point for every correct answer and lost 0.5 points for every incorrect answer.James

Nuetrik [128]

Answer:

Step-by-step explanation:

6x0.5=3-12=9

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3 years ago

Determine the probability of randomly selecting two individuals who are issued exactly two credit cards. [Hint: Are the events

pishuonlain [190]

Answer:

They are dependent because we have to select from people who are given cards.

Step By Step Explanation:

So we'll take away people not given cards first den find the probability of selecting people with cards over the total number of people present .

Probability we'll be equal to = number of people with card(C) two persons/total number of people

Where C represent combination

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3 years ago

Explain why 1/2 is not equivalent to 2/5.

juin [17]

Find ing the common denominator would make it 10.
for 1/2 to get to 10 you have to multiply by 5
1/2x5= 5/10
then you have to convert 2/5 to get the denominator to be 10
so you multiply 2/5 by 2
2/5x2= 4/10
5/10 is greater than 4/10

7 0

3 years ago

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