Total Cost = 250 + 60x is the equation that models the given situation
<em><u>Solution:</u></em>
Given that, Linda's start up cost for her online jewelery store was $250
She has to pay an additional $60 per month to keep it running
To find: Equation that models this situation
From given,
Start up cost = $ 250
Let "x" be the number of months she keeps the store running
Additional pay per month = $ 60
Thus, the total cost Linda spend to keep the store running is given as:
Total Cost = Startup cost + (Additional pay per month)(number of months)
Thus the equation that models the given situation is found
Hello there, Lithommie
You see accroding to newtons gravitational law an object that weighs more on earth wieghs less in space due to the lack of strenthness of gravity.
If my answer helped you understand more clearly i would glady apriciate brainliest thank you and have a great day!
So I'm going to assume that this question is asking for <u>non extraneous solutions</u>, or solutions that are found in the equation <em>and</em> are valid solutions when plugged back into the equation. So firstly, subtract 2 on both sides of the equation:
Next, square both sides:
Next, subtract x and add 2 to both sides of the equation:
Now we are going to be factoring by grouping to find the solution(s). Firstly, what two terms have a product of 6x^2 and a sum of -5x? That would be -3x and -2x. Replace -5x with -2x - 3x:
Next, factor x^2 - 2x and -3x + 6 separately. Make sure that they have the same quantity on the inside of the parentheses:
Now you can rewrite the equation as 
Now, apply the Zero Product Property and solve for x as such:
Now, it may appear that the answer is C, however we need to plug the numbers back into the original equation to see if they are true as such:
Since both solutions hold true when x = 2 and x = 3, <u>your answer is C. x = 2 or x = 3.</u>
(a+15.25)=x cost of each tree
(a•15)=110 cost of all the shrub
(x•5)= 101.25 cost of all trees
110+101.25= 211.25
equatiin all together
[(a+15.25)×5]+(a×15)=211.25
