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Answer:25
Step-by-step explanation: first you do 5+12 which gets you 17. Then you add 17+8 and you get 25. 25 -8=17 17-12=5
You're given that φ is an angle that terminates in the third quadrant (III). This means that both cos(φ) and sin(φ), and thus sec(φ) and csc(φ), are negative.
Recall the Pythagorean identity,
cos²(φ) + sin²(φ) = 1
Multiply the equation uniformly by 1/cos²(φ),
cos²(φ)/cos²(φ) + sin²(φ)/cos²(φ) = 1/cos²(φ)
1 + tan²(φ) = sec²(φ)
Solve for sec(φ) :
sec(φ) = - √(1 + tan²(φ))
Given that cot(φ) = 1/4, we have tan(φ) = 1/cot(φ) = 1/(1/4) = 4. Then
sec(φ) = - √(1 + 4²) = -√17
The parabola will show the vertex in the format: y-k = (x-h)^2, where the vertex point
lies at (h, k).

let's first put it in "y =" standard format:

Since we cannot get a perfect square out of this, we complete the square: a=1, b=2, c=3
(b/2)^2 = (2/2)^2 = 1, so

So there's +2 leftover, since 3-1=2; so:

Now we'll subtract the 2 from both sides to show our vertex:

where our vertex (h, k) is at (-1, 2)