Answer:

Step-by-step explanation:
We want to find an equivalent expression for
![(\sqrt[4]{9})^{ \frac{1}{2}x}](https://tex.z-dn.net/?f=%20%28%5Csqrt%5B4%5D%7B9%7D%29%5E%7B%20%5Cfrac%7B1%7D%7B2%7Dx%7D%20%20)
To find an equivalent expression, we need to apply the following property of exponents:
![{a}^{ \frac{m}{n}}=( \sqrt[n]{ {a}} )^{m}](https://tex.z-dn.net/?f=%20%7Ba%7D%5E%7B%20%5Cfrac%7Bm%7D%7Bn%7D%7D%3D%28%20%5Csqrt%5Bn%5D%7B%20%7Ba%7D%7D%20%20%29%5E%7Bm%7D%20)
We let a=9, n=4 and m=½x
Then :
![{9}^{ \frac{ \frac{1}{2}x}{4}}=( \sqrt[4]{ {9}} )^{ \frac{1}{2}x}](https://tex.z-dn.net/?f=%20%7B9%7D%5E%7B%20%5Cfrac%7B%20%5Cfrac%7B1%7D%7B2%7Dx%7D%7B4%7D%7D%3D%28%20%5Csqrt%5B4%5D%7B%20%7B9%7D%7D%20%20%29%5E%7B%20%5Cfrac%7B1%7D%7B2%7Dx%7D%20)
Simplify the left hand side to get:
![{9}^ {\frac{1}{8}x} =( \sqrt[4]{ {9}} )^{ \frac{1}{2}x}](https://tex.z-dn.net/?f=%7B9%7D%5E%20%7B%5Cfrac%7B1%7D%7B8%7Dx%7D%20%3D%28%20%5Csqrt%5B4%5D%7B%20%7B9%7D%7D%20%20%29%5E%7B%20%5Cfrac%7B1%7D%7B2%7Dx%7D%20)
Therefore the correct answer is:

Answer:

Step-by-step explanation:


![x[2x(x-2)+1(x-2)]](https://tex.z-dn.net/?f=x%5B2x%28x-2%29%2B1%28x-2%29%5D)

Yes. just multiply 2x19= 38
Answer:
Undefined
Step-by-step explanation:
The square root of a negative number does not exist in the set of real numbers so it would be Undefined