How is a line segment different from a line? How is a line segment different from a ray
1 answer:
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Given:
The data set is
21, 16, 30, 15, 16, 18, 10, 24, 26, 20, 19, 24, 24, 25, 23
10, 15, 16, 16, 18, 19, 20, 21, 23, 24, 24, 24, 25, 26, 30
To find:
The range, average and median for the given data set.
Solution:
Arrange the data set in ascending order.
10, 15, 16, 16, 18, 19, 20, 21, 23, 24, 24, 24, 25, 26, 30
(1)
Range = Maximum value - Minimum value
= 30 - 10
= 20
Therefore, the range of the given data set is 20. All the options are incorrect.
(2)
Therefore, the average score is about 20.73. All the options are incorrect.
(3)
Number of observations = 15, which is odd.
In the arranged data set 8th term is 21.
Therefore, the correct option is b.
Answer:
P [ 55 ≤ X ≤ 70 ] = 23.55 %
Step-by-step explanation:
We know:
μ₀ = mean of population σ = standard deviation
We begin for calculating the probability of X ≤ 55 so
Step 1:
μ₀ = 50 σ = 7
×₁ = ( μ - μ₀ ) ÷ σ ⇒ ×₁ = (55-50) ÷ 7 ⇒ ×₁ = 5 ÷ 7 ×₁ = 0.7143
We look z table and we have to interpolate
value (closest smaller Than ×₁ 0.71 and closest bigger than ×₁ 0.72
The associated area for these point are: 0.7611 and 0.7642
Taking diferences and by rule of three
0.01 ⇒ 0.0031
0.0042 ⇒ Δ Δ = 0.0013 and Area for ×₁ = 0.7624
That is the probability of X ≤ 55
Now we have to find the probability of X ≤ 70
We procede as in step 1
μ₀ = 50 σ = 7
×₂ = ( μ - μ₀ ) ÷ σ ⇒ ×₂ = (70-50) ÷ 7 ⇒ ×₂ = 20 ÷ 7 ×₂ = 2.8571
We look z table and we have to interpolate
for 2.85 ⇒ 0.9978 (area) 2.8571 - 2.85 = 0.007
for 2.86 ⇒ 0.9979 (area)
Therefore by rule of three we have
0.01 ⇒ 0.0001
0.007 ⇒ Δ Δ = 0.00007
And area for ×₂ = 2.8571 is equal to 0.99787 and the probability of
X ≤ 0.99787 or 99.79
Now if we look the annex drawing (the area we are looking for is enclose for the values x₁ and ×₂ (pink area) and is the diference between these two areas
So P [ 55 ≤ X ≤ 70 ] is 99.79 % - 76.24 % = 23.55
