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Mrrafil [7]
3 years ago
11

You were billed $28.50 for additional data usage on your cell phone at a rate of $9 per gigabyte. Three choices are correct ways

to calculate the additional gigabytes, g, that you used. Which choice is NOT? (9g=28.5) (9g=28.5) ( 28.5=9⋅g) (28.59=g)
Mathematics
2 answers:
tester [92]3 years ago
6 0

Answer: 28.59=g is incorrect.

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

Bill for additional data usage: $28.50

Cost per gigabyte: $9

To calculate the additional gigabytes we have to write an expression where the total bill ($28.5) is equal to the gigabytes used (g) multiplied by the cost per gigabyte.

Mathematically speaking:

28.5 = 9g

The three first options are correct (one is put in a different order but is the same expression). So, the incorrect option is (28.59=g).

Vika [28.1K]3 years ago
3 0

Answer:

The answer 28.59=g

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Answer: 
x = 2

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vaieri [72.5K]

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3 0
3 years ago
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A package weighs P pounds P being a whole number. to ship this package by express costs one dollar and sixty five cents for the
deff fn [24]
Whole package weighs 20pounds

1.65 = 5pounds
0.12 = extra pound

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5 0
3 years ago
The weight of a small Starbucks coffee is a normally distributed random variable with a mean of 330 grams and a standard deviati
just olya [345]

Answer:

Weights of at least 340.1 are in the highest 20%.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 330, \sigma = 12

a. Highest 20 percent

At least X

100-20 = 80

So X is the 80th percentile, which is X when Z has a pvalue of 0.8. So X when Z = 0.842.

Z = \frac{X - \mu}{\sigma}

0.842 = \frac{X - 330}{12}

X - 330 = 12*0.842

X = 340.1

Weights of at least 340.1 are in the highest 20%.

3 0
3 years ago
WILL GIVE BRAINLIESTTTT, FIVESTARS ANDTHANKS<br> PLEASEHELP
SpyIntel [72]

Answer:

3 is the answer

Step-by-step explanation:

answer up above

7 0
3 years ago
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