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Wittaler [7]
3 years ago
6

your speed is constant if you are traveling in a straight line with an acceleration of zero. true or false?

Mathematics
2 answers:
Yuki888 [10]3 years ago
8 0
You do not have a speed if you are not moving

Drupady [299]3 years ago
4 0
True

acceleration means change of velocity
since you are traveling in striaight line and accelartion =0, speed must be constant since when you accelerate, y ou speed up or slow down


true
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PLSSS HELP ASAPPP I'LL GIVE YOU BRAINLIEST IF I GET IT RIGHT!!!​
kondor19780726 [428]

Answer:

D. 76

Step-by-step explanation:

because students that has 5 absences and less most likely to get higher than 75 marks. The student who has 8 absences studied at home, he's a genius

3 0
2 years ago
Solve using Fourier series.
Olin [163]
With 2L=\pi, the Fourier series expansion of f(x) is

\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos\dfrac{n\pi x}L+\sum_{n\ge1}b_n\sin\dfrac{n\pi x}L
\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos2nx+\sum_{n\ge1}b_n\sin2nx

where the coefficients are obtained by computing

\displaystyle a_0=\frac1L\int_0^{2L}f(x)\,\mathrm dx
\displaystyle a_0=\frac2\pi\int_0^\pi f(x)\,\mathrm dx

\displaystyle a_n=\frac1L\int_0^{2L}f(x)\cos\dfrac{n\pi x}L\,\mathrm dx
\displaystyle a_n=\frac2\pi\int_0^\pi f(x)\cos2nx\,\mathrm dx

\displaystyle b_n=\frac1L\int_0^{2L}f(x)\sin\dfrac{n\pi x}L\,\mathrm dx
\displaystyle b_n=\frac2\pi\int_0^\pi f(x)\sin2nx\,\mathrm dx

You should end up with

a_0=0
a_n=0
(both due to the fact that f(x) is odd)
b_n=\dfrac1{3n}\left(2-\cos\dfrac{2n\pi}3-\cos\dfrac{4n\pi}3\right)

Now the problem is that this expansion does not match the given one. As a matter of fact, since f(x) is odd, there is no cosine series. So I'm starting to think this question is missing some initial details.

One possibility is that you're actually supposed to use the even extension of f(x), which is to say we're actually considering the function

\varphi(x)=\begin{cases}\frac\pi3&\text{for }|x|\le\frac\pi3\\0&\text{for }\frac\pi3

and enforcing a period of 2L=2\pi. Now, you should find that

\varphi(x)\sim\dfrac2{\sqrt3}\left(\cos x-\dfrac{\cos5x}5+\dfrac{\cos7x}7-\dfrac{\cos11x}{11}+\cdots\right)

The value of the sum can then be verified by choosing x=0, which gives

\varphi(0)=\dfrac\pi3=\dfrac2{\sqrt3}\left(1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots\right)
\implies\dfrac\pi{2\sqrt3}=1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots

as required.
5 0
3 years ago
Nick and Tasha are buying supplies for a camping trip. They need to buy chocolate bars to make s’mores, their favorite campfire
Harlamova29_29 [7]

Answer:

9/10

Step-by-step explanation:

first you find the lowest common denominator. 1/2 becomes 5/10, 2/5 becomes 4/10. 5/10+4/10=9/10

7 0
3 years ago
Here is the question: Jamey purchased a new boat for 61014.00. She read that the value of the new boats change by -2/19 in the f
olga55 [171]

The value of Jamey's boat after the first year of purchase is <u>$54,591.47</u>.

<h3>What is a reduction in value?</h3>

The change in the value of the new boat can be described as a reduction in value, which is akin to the depreciation of the initial value.

The reduction means that the value of the boat fell after the first year of use.

The reduction or change in value and the new value after the first year can be computed as follows:

<h3>Data and Calculations:</h3>

Purchase price = $61,014

Change in value after first year = -2/19

Change in value (dollars) = $6,422.53 ($61,014 x 2/19)

Value after the first year = $54,591.47 ($61,014 - $6,422.53)

Thus, the value of Jamey's boat after the first year of purchase is <u>$54,591.47</u>.

Learn more about reduction in the value of an asset at brainly.com/question/25806993

#SPJ1

6 0
2 years ago
A cell phone company has a basic monthly plan of $40 plus $0.45 for any minutes used over 700. Before receiving his statement, J
Serga [27]

Ok so we know he used over 700 because he was charged more than 40. Then we take the $8.10 and divide 0.45 into it. This then gives you 18 more minutes. Then add 18 to 700 and you get 718 min.
4 0
3 years ago
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