Answer:
A.
Explanation:
Our values are defined by,
We can express also in a vectorial way, then
no values in 
Acceleration as follow,
We know that velocity is given by,
We need to calculate for t=3, then
Our mass is 1000Kg, so the momentum is
Answer:
True
Explanation:
The earths gravitational pull keeps it consistent with its orbit.
Walking at a speed of 2.1 m/s, in the first 2 s John would have walked
(2.1 m/s) (2 s) = 4.2 m
Take this point in time to be the starting point. Then John's distance from the starting line at time <em>t</em> after the first 2 s is
<em>J(t)</em> = 4.2 m + (2.1 m/s) <em>t</em>
while Ryan's position is
<em>R(t)</em> = 100 m - (1.8 m/s) <em>t</em>
where Ryan's velocity is negative because he is moving in the opposite direction.
(b) Solve for the time when they meet. This happens when <em>J(t)</em> = <em>R(t)</em> :
4.2 m + (2.1 m/s) <em>t</em> = 100 m - (1.8 m/s) <em>t</em>
(2.1 m/s) <em>t</em> + (1.8 m/s) <em>t</em> = 100 m - 4.2 m
(3.9 m/s) <em>t</em> = 95.8 m
<em>t</em> = (95.8 m) / (3.9 m/s) ≈ 24.6 s
(a) Evaluate either <em>J(t)</em> or <em>R(t)</em> at the time from part (b).
<em>J</em> (24.6 s) = 4.2 m + (2.1 m/s) (24.6 s) ≈ 55.8 m
Answer:
3.84 m/s
Explanation:
Using Bernoulli's equation below:
P1 + (1/2ρv1²) + h1ρg = P2 + (1/2ρv2²) + h2ρg
where P1 = P2 atmospheric pressure
(1/2ρv1²) + h1ρg = (1/2ρv2²) + h2pg
collect the like terms
h1ρg - h2ρg = (1/2ρv2²) - (1/2ρv1²)
factorize the expression by removing the like terms on both sides
gρ(h1 - h2) = 1/2ρ( v2² - v1²)
divide both side by rho (density in kg/m³, ρ )
g(h1 - h2) = 1/2 (v2² - v1²)
assuming the surface of the tank is large and the speed of water then at the tank surface v1 = 0
2g(h1 - h2) = v2²
take the square root of both side and h1 - h2 is the difference between the surface of the tank and the opening where water is coming out in meters
√2g(h1 - h2) = √ v2²
v2 = √2g(h1-h2) = √ 2 × 9.81×0.75 = 3.84 m/s
