Once the magma found at location "E" cools and crystalizes, it will

What is the frequency of a wave if the wave speed is 24 m/s and the wavelength is 2m?

fredd [130]

The formula F=velocity/wavelength
F=24/2
F=12 Hz

4 0

3 years ago

6. Jones covered a distance of 50 miles on his first trip. On a later trip he traveled 300 miles while going three times as fast

nata0808 [166]

<h3>given:</h3>

first trip= 50 miles.

second trip= 300 miles.

his new time compared to the old time.

<h3>solution:</h3>

Let speed of the 1st trip x miles / hr. and speed of the 2nd trip 3x / hr.

Speed = Distance/Time

So, times taken to covered a distance of 50 miles on his first trip = 50/x hr.

= 100/x hr

Therefore, his new time compared with the old time was twice as much.

answer= b) twice as much

5 0

2 years ago

At what point on the paraboloid y = x2 z2 is the tangent plane parallel to the plane 3x 2y 5z = 8?

salantis [7]

To find the tangent plane to the surface f(x,y,z)=0 at a point (X,Y,Z) we use the following method:

Calculate grad f = (f_x, f_y, f_z). The normal vector to the surface at the point (X,Y,Z) is grad f(X,Y,Z). The equation of a plane with normal vector n which passes through the point p is (r-p).n=0, where r=(x,y,z) is the position vector. So the equation of the tangent plane to the surface through the point (X,Y,Z) is ((x,y,z)-(X,Y,Z)).grad f(X,Y,Z)=0. 

Now in your case we have f(x,y,z)=y-x^2-z^2, so grad f=(-2x,1,-2z), and the equation of the tangent plane at the point (X,Y,Z) is 

((x,y,z)-(X,Y,Z)).(-2X,1,-2Z)=0, 

that is 

-2X(x-X)+1(y-Y)-2Z(z-Z)=0, 

i.e. 

-2Xx+y-2Zz = -2X^2+Y-2Z^2. (1) 

Now compare this equation with the plane 

x + 2y + 3z = 1. (2) 

The two planes a_1x+b_1y+c_1z=d_1, a_2x+b_2y+c_2z=d_2 are parallel when (a_1,b_1,c_1) is a multiple of (a_2,b_2,c_2). So the two planes (1),(2) are parallel when (-2X,1,-2Z) is a multiple of (1,2,3), and we have 

(-2X,1,-2Z)=1/2(1,2,3) 

for X=-1/4 and Z=-3/4. On the paraboloid the corresponding y coordinate is Y=X^2+Z^2=1^4+9^4=5/2. 

So the tangent plane to the given paraboloid at the point (-1/4,5/2,-3/4) is parallel to the given plane.

6 0

3 years ago

This is one of those special bounce collisions that is perfectly elastic. It is worth knowing that when identical masses collide

Dmitrij [34]

Answer:

0.069 J

Explanation:

mass of first ball (M1) = 0.839 kg

mass of second ball (M2) = 0.839 kg

initial velocity of first ball (U1) = 0.406 m/s

initial velocity of second ball (U2) = 0 m/s

For head on elastic collisions of equal masses, the velocities of the masses always changes.and this has also been clearly stated in the question. Hence the velocity if mass A will interchange with that of mass B after collision.

therefore

final velocity of first ball (V1) = 0 m/s

final velocity of second ball (V2) = 0.406 m/s

kinetic energy of second ball after collision = 0.5m $v^{2}$

= 0.5 x 0.839 x 0.406 x 0.406 = 0.069 J

6 0

3 years ago

If a body system, such as the digestive system, fails to work properly, what would happen to the organism

agasfer [191]

It would die from the lack of nourishment

3 0

3 years ago