Answer:
The acceleration is 
and the distance covered is 97.17 m.
Explanation:
Given that,
Initial speed of an automobile, u = 60 km/hr = 16.67 m/s
Final speed of an automobile, v = 80 km/hr = 22.2 m/s
Time, t = 5 s
We need to find the acceleration of the car and the distance traveled in this 5 sec interval. Let a is the acceleration. Using the definition of acceleration as :
Let d is the distance covered. Using the third equation of motion to find it as follows :
So, the acceleration is and the distance covered is 97.17 m.
Answer:
W = 307.45 joules
Explanation:
the work done is defined as the product of force applied in the direction of displacement and the displacement.
Use the formula for work directly
(work) = (force) x (displacement)
Work is a scalar quantity and its SI unit is Joule.
W = F x d
F = 71.5 N
d = 4.30 m
W = 71.5 × 4.30
W = 307.45 joules
use the equations provided it shouldn't he hard
The fundamental frequency of the open pipe A
Length 'L₀' is, f₀ = U/2L₀ = 340 H₂
the speed of sound in air V= 343m/s
∴343/2L₀ = 340 → length L₀ = 343/2 ×340 = 0.5044 = 50.44
The third harmonic of closed pipe 'B' is
F3₀ = 3V/4LC
The second harmonic of open pipe 'A' is
f2₀ = 2V/2L₀
∴ 3V/4LC = 2V/2L →L₀ = 3L₀/4
⇒ The length of closed pipe B is
Lc = 37.83cm
