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Dmitry [639]
3 years ago
6

Once the magma found at location "E" cools and crystalizes, it will

Physics
1 answer:
Paha777 [63]3 years ago
7 0
Turn into stone. this will cause erosion for magma to turn to stone
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An automobile accelerates uniformly from a speed of 60 km/hr (16.67 m/s) to a speed of 80 km/hr (22.2 m/s) in 5 s. Determine the
monitta

Answer:

The acceleration is 1.106\ m/s^2 and the distance covered is 97.17 m.

Explanation:

Given that,

Initial speed of an automobile, u = 60 km/hr = 16.67 m/s

Final speed of an automobile, v = 80 km/hr = 22.2 m/s

Time, t = 5 s

We need to find the acceleration of the car and the distance traveled in this 5 sec interval.  Let a is the acceleration. Using the definition of acceleration as :

a=\dfrac{v-u}{t}\\\\a=\dfrac{22.2-16.67}{5}\\\\a=1.106\ m/s^2

Let d is the distance covered. Using the third equation of motion to find it as follows :

v^2-u^2=2as\\\\s=\dfrac{v^2-u^2}{2a}\\\\s=\dfrac{(22.2)^2-(16.67)^2}{2\times 1.106}\\\\s=97.17\ m

So, the acceleration is 1.106\ m/s^2 and the distance covered is 97.17 m.

7 0
3 years ago
In a step-down transformer, which describes the primary winding compared with the secondary winding? A higher voltage and fewer
kirill115 [55]
B. Higher voltage and more coils of wire :)

7 0
3 years ago
Read 2 more answers
Calculate the work done by an applied force of 71.5 N on a crate for the following. (Include the sign of the value in your answe
Nastasia [14]

Answer:

W = 307.45 joules

Explanation:

the work done is defined as the product of force applied in the direction of displacement and the displacement.

Use the formula for work directly

(work) = (force) x (displacement)

Work is a scalar quantity and its SI unit is Joule.

W = F x d

F = 71.5 N

d = 4.30 m

W = 71.5 × 4.30

W = 307.45 joules

8 0
3 years ago
I Need Help With This
timama [110]

use the equations provided it shouldn't he hard

5 0
3 years ago
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Organ pipe a, with both ends open, has a fundamental frequency of 340 hz. the third harmonic of organ pipe b, with one end open,
Sphinxa [80]
The fundamental frequency of the open pipe A
Length 'L₀' is, f₀ = U/2L₀ = 340 H₂
the speed of sound in air V=  343m/s
∴343/2L₀ = 340 → length L₀ = 343/2 ×340 = 0.5044 = 50.44
The third harmonic of closed pipe 'B' is 
F3₀ = 3V/4LC
The second harmonic of open pipe 'A'  is
f2₀ = 2V/2L₀
∴ 3V/4LC = 2V/2L →L₀ = 3L₀/4
⇒ The length of closed pipe B is 
Lc = 37.83cm

7 0
3 years ago
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