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spin [16.1K]
3 years ago
13

Find the area of a rectangle with the following dimensionsLength=×+3Width=4​

Mathematics
1 answer:
grigory [225]3 years ago
3 0

Answer:

4x+12

Step-by-step explanation:

The area of a rectangle is given by

A = l*w

A = (x+3) *4

Distribute

A = 4x+12

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Can someone please help me solve this? <br><br> 2x+5y=-1 <br><br> -10x-25y=5
fredd [130]

this is system of equations

2x + 5y = -1   times this one by 5 to make the y's opposite

-10x -25y = 5

10x - 25y = -5  (this is it times by 5, now add them)

__________

0 + 0       = 0    

now since everything cancels and both sides are equal it has infinite solutions beaus they are actually the same line.  


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Step-by-step explanation:

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2 years ago
Could someone please explain/help me to do this using Pythagoras theorem?
alex41 [277]

Answer:

\boxed{478.02}

Step-by-step explanation:

→ First understand what Pythagoras theorem is

Pythagoras is a theorem used to find the hypotenuse (the side opposite to the right-angle) of a triangle. We would need the base lengths as well the height in order to use Pythagoras.

→ State the formula and identify the letters

a² + b² = c² ⇒ where 'a' is 380cm, 'b' is 290cm and 'c' is what we are trying to work out

→ Substitute in the values into the formula

380² + 290² = c²

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144400 + 84100 = c²

⇒ Collect the numbers together

228500 = c²

⇒ Square root both sides to find 'c'

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8 0
3 years ago
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Bingel [31]

Answer:

1 and -5

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~~~~~x^3+3x^2-9x+5=0\\\\\implies x^3-x^2+4x^2-4x-5x+5=0\\\\\implies x^2(x-1)+4x(x-1)-5(x-1)=0\\\\\implies (x-1)(x^2 +4x -5) = 0\\\\\implies (x-1)(x^2+5x -x -5) = 0\\\\\implies (x-1)[x(x+5) -(x+5)] =0\\\\\implies (x-1)(x-1)(x+5)= 0\\\\\implies (x-1)^2(x+5) = 0\\\\\implies x = 1,~~ x = -5

6 0
2 years ago
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