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3 years ago

Solve the following system of equations by elimination. Express

1 answer:

4 0

Add the two equations together with the same variables

-x+4x=3x
-3y+3y=0
20+1=21

You now get

3x=21

Divide and find x =7

Plug in x to the equation to find y
Y=-9

(7,-9)

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In a football tournament, the Bees scored 9 less than three times as many points as the Hornets. The Wasps scored 28 more points

Elina [12.6K]

Given:

Bees scored 9 less than three times as many points as the Hornets.

Wasps scored 28 more points than the Hornets.

Together the three teams scored 184 points.

To find:

The required equation for this scenario.

Step-by-step explanation:

Let x represent the number of points scored by the Hornets.

Bees scored 9 less than three times as many points as the Hornets.

Bees score = 3x-9

Wasps scored 28 more points than the Hornets.

Wasps score = x+28

Together the three teams scored 184 points.

$(3x-9)+x+(x+28)=184$

Therefore, the required equation is $(3x-9)+x+(x+28)=184$ .

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3 years ago

Convert 2000 centimeters to inches

Free_Kalibri [48]

Answer:

787.4016 inches

Step-by-step explanation:

6 0

1 year ago

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PLEASE HELP!!!!!!!!!!!

Art [367]

green pepper, onion, tomato

= 2x, 5x, 9x

Number of cups = 96

therefore 2x + 5x + 9x = 96

16x=96

x= 96÷16 = 6

Onion = 5x

therefore answer = 6 x 5 = 30

C. 30 is the correct answer :)

6 0

3 years ago

If x>2, then x^2-x-6/x^2-4=

Viefleur [7K]

Consider the expression $\frac{x^{2} -x-6}{ x^{2} -4}$

To factorize the expression in the denominator we use difference of squares: $x^{2} -4=x^{2} - 2^{2} =(x-2)(x+2)$

To factorize $x^{2} -x-6$ we use the following method:

$x^{2} -x-6=(x-a)(x-b)$

where a, b are 2 numbers such that a+b= -1, the coefficient of x,

and a*b= -6, the constant.

such 2 numbers can be easily checked to be -3 and 2

(-3*2=6, -3+2=-1)

So $x^{2} -x-6=(x-a)(x-b)=(x+3)(x-2)$

$
 \frac{x^{2} -x-6}{ x^{2} -4}= \frac{(x+3)(x-2)}{(x-2)(x+2)}= \frac{x+3}{x+2}$

$\frac{x+3}{x+2}= \frac{x+2+1}{x+2}= \frac{x+2}{x+2}+ \frac{1}{x+2}=1+ \frac{1}{x+2}$

for x>2

$\frac{1}{x+2}\ \textless \ \frac{1}{2+2}= \frac{1}{4}$

thus

for x>2,

$1+ \frac{1}{x+2}\ \textless \ 1+ \frac{1}{4}= \frac{5}{4}$

Answer:

for x>2

$\frac{x^{2} -x-6}{ x^{2} -4} = \frac{x+3}{x+2} \ \textless \ \frac{5}{4}$ , (but the expression is never 0)

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3 years ago

Graph f(x)=-2|x+4| khan academy

Vladimir [108]

Answer:

Step-by-step explanation:

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3 years ago

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