If UT is the midsegment of QRS, then SQ = 2(2x + 2) = 4x + 4
Then,
(3x + 1)/(7x - 1) = (2x + 2)/(4x + 4) = 1/2
2(3x + 1) = 7x - 1
6x + 2 = 7x - 1
7x - 6x = 2 + 1
x = 3
Therefore, SQ = 4(3) + 4 = 12 + 4 = 16.
Answer:
five thousand one hundred seventy nine
Step-by-step explanation:
Answer:
It will be the one with 10c
second line right
16 + 4x + 2x - 3x + x = 0
First, simplify 16 + 4x + 2x - 3x + x to get 16 + 4x. / Your problem should look like: 16 + 4x = 0
Second, subtract 16 from both sides. / Your problem should look like: 4x = -16
Third, divide both sides by 4. / Your problem should look like: x =
Fourth, simplify

to get 4. / Your problem should look like: x = -4
Answer:
x = -4