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attashe74 [19]
3 years ago
9

How do you find volume of a circle

Mathematics
1 answer:
Sauron [17]3 years ago
5 0

Answer:

V = 4/3 pi r^3  for a sphere

Step-by-step explanation:

You can't a circle is a two dimensional object.

The volume of a sphere, which is the three dimensional form of a circle is found by

V = 4/3 pi r^3

Where r is the radius

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Use the method illustrated in the solutions to Exercise 9.2.39 to answer the following questions. (a) How many ways can the lett
Jobisdone [24]

Answer:

(a) 720 ways

(b) 120 ways

(c) 24 ways

Step-by-step explanation:

Given

Word = DANCER

n =6 --- number of letters

Solving (a): Number of arrangements.

We have:

n =6

So, the number of arrangements is calculated as:

Total =n!

This gives:

Total =6!

This gives:

Total =6*5*4*3*2*1

Total =720

Solving (b): DA as a unit

DA as a unit implies that, we have:

[DA] N C E R

So, we have:

n = 5

So, the number of arrangements is calculated as:

Total =n!

This gives:

Total =5!

This gives:

Total =5*4*3*2*1

Total =120

Solving (c): NCE as a unit

NCE as a unit implies that, we have:

D A [NCE] R

So, we have:

n = 4

So, the number of arrangements is calculated as:

Total =n!

This gives:

Total =4!

This gives:

Total =4*3*2*1

Total =24

8 0
2 years ago
Ken, a single taxpayer, has a gross income of $79,685. He claims one exemption and can take a deduction of $1,257 for medical ex
Ganezh [65]
The answer is c. $12,675 just took the test 
4 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%24a%2Ba%20r%2Ba%20r%5E%7B2%7D%2B%5Cldots%20%5Cinfty%3D15%24%24a%5E%7B2%7D%2B%28a%20r%29%5E%7B
riadik2000 [5.3K]

Let

S_n = \displaystyle \sum_{k=0}^n r^k = 1 + r + r^2 + \cdots + r^n

where we assume |r| < 1. Multiplying on both sides by r gives

r S_n = \displaystyle \sum_{k=0}^n r^{k+1} = r + r^2 + r^3 + \cdots + r^{n+1}

and subtracting this from S_n gives

(1 - r) S_n = 1 - r^{n+1} \implies S_n = \dfrac{1 - r^{n+1}}{1 - r}

As n → ∞, the exponential term will converge to 0, and the partial sums S_n will converge to

\displaystyle \lim_{n\to\infty} S_n = \dfrac1{1-r}

Now, we're given

a + ar + ar^2 + \cdots = 15 \implies 1 + r + r^2 + \cdots = \dfrac{15}a

a^2 + a^2r^2 + a^2r^4 + \cdots = 150 \implies 1 + r^2 + r^4 + \cdots = \dfrac{150}{a^2}

We must have |r| < 1 since both sums converge, so

\dfrac{15}a = \dfrac1{1-r}

\dfrac{150}{a^2} = \dfrac1{1-r^2}

Solving for r by substitution, we have

\dfrac{15}a = \dfrac1{1-r} \implies a = 15(1-r)

\dfrac{150}{225(1-r)^2} = \dfrac1{1-r^2}

Recalling the difference of squares identity, we have

\dfrac2{3(1-r)^2} = \dfrac1{(1-r)(1+r)}

We've already confirmed r ≠ 1, so we can simplify this to

\dfrac2{3(1-r)} = \dfrac1{1+r} \implies \dfrac{1-r}{1+r} = \dfrac23 \implies r = \dfrac15

It follows that

\dfrac a{1-r} = \dfrac a{1-\frac15} = 15 \implies a = 12

and so the sum we want is

ar^3 + ar^4 + ar^6 + \cdots = 15 - a - ar - ar^2 = \boxed{\dfrac3{25}}

which doesn't appear to be either of the given answer choices. Are you sure there isn't a typo somewhere?

7 0
2 years ago
Help me please need it fast
Sonja [21]

Answer:I am pretty sure it is A

Step-by-step explanation:

6 0
3 years ago
Find sin θ if θ is in Quadrant III and tan θ = . 0.958
Leokris [45]
Use the following identities:
sec^2 = 1  + tan^2 \\  \\ sec = \frac{1}{cos} \\  \\ sin^2 = 1 - cos^2
Also because the angle is in quadrant 3, sin must be negative.
Therefore
sin = - \sqrt{1 - \frac{1}{1 + tan^2}}
Subbing in tan = 0.958
sin \theta = -0.69178
7 0
2 years ago
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