The derivative of the function g(x) as given in the task content by virtue of the Fundamental theorem of calculus is; g'(x) = √2 ln(t) dt = 1.
<h3>What is the derivative of the function g(x) by virtue of the Fundamental theorem of calculus as given in the task content?</h3>
g(x) = Integral; √2 ln(t) dt (with the upper and lower limits e^x and 1 respectively).
Since, it follows from the Fundamental theorem of calculus that given an integral where;
Now, g(x) = Integral f(t) dt with limits a and x, it follows that the differential of g(x);
g'(x) = f(x).
Consequently, the function g'(x) which is to be evaluated in this scenario can be determined as:
g'(x) =
= 1
The derivative of the function g(x) as given in the task content by virtue of the Fundamental theorem of calculus is; g'(x) = √2 ln(t) dt = 1.
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Answer:

Step-by-step explanation:
Given,
Cost price of three thermos flask = 1080
Selling price of each thermos flask = 400
<u>Finding </u><u>the </u><u>selling </u><u>price </u><u>of </u><u>three </u><u>thermos </u><u>flask</u>
Since, the cost of 3 thermos flask is more than that of 1 thermos flask. So, the cost of 1 thermos flask is multiplied by 3 ( i.e 400 × 3 = 1200 )
Here, the selling price is greater than cost price.
So, there is profit.
And we know that,

⇒
⇒
Profit amount = 120
<u>Finding </u><u>the </u><u>profit </u><u>percentage</u>

⇒
⇒
Hope I helped!
Best regards!!
This expression is a difference of squares:

Answer:
Because alternate exterior angles are congruent
Step-by-step explanation:
Answer: 3.75z+12
For an equivalent expression, lets simplify the equation.
3/4(5z+16)
multiply both '5z' and '16' by 3/4
3.75z+12