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3 years ago

Answer 9 a and b and c

Mathematics

1 answer:

inn [45]3 years ago

3 0

If she can only work 15 hours a week and earns $7 per hour, just multiply 7 by 15 and you'll have your answer :)

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Two thirds as a decimal

larisa [96]

2/3
=0.6666666... is your final answer. Hope it help!

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3 years ago

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Does anyone know what the slope should be

Lemur [1.5K]

The slope is 4/3.

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2 years ago

Find the value of sin30+tan^(2)60+sec^(2)45

xenn [34]

Answer:

Step-by-step explanation:

sin 30+tan²(60)+sec²(45)

=1/2+ (√3)^2+(√2)²

=1/2+3+2

=5 1/2

=5.5

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2 years ago

What is the factored term form of 2x^3+4x^2-x

Westkost [7]

Answer: $x(2x^2+4x-1)$

Step-by-step explanation:

2x³+4x²-x, first find the Greatest Common Factor (GCF), which is x. To find the GCF, look at what all the numbers have in common, and then see if it has the greatest value. Next factor out the GCF.

$x(\frac{2x^3}{x} + \frac{4x^2}{x}-\frac{x}{x} )$ Simplify each term in the parentheses.

$x(2x^2+4x-1)$

Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! :-)

- Cutiepatutie ☺❀❤

8 0

3 years ago

According to a study done by a university student, the probability a randomly selected individual will not cover his or her mou

VikaD [51]

Complete Question

The complete question is shown on the first uploaded image

Answer:

$P(X = 8) = 0.0037$

$P(X < 5) = 0.805$

$P(X > 6) = 0.0206$

I would be surprised because the value is very small , less the 0.05

Step-by-step explanation:

From the question we are told that

The probability a randomly selected individual will not cover his or her mouth when sneezing is $p = 0.267$

Generally data collected from this study follows binomial distribution because the number of trials is finite , there are only two outcomes, (covering , and not covering mouth when sneezing ) , the trial are independent

Hence for a randomly selected variable X we have that

$X \ \ \~ \ \ { B ( p , n )}$

The probability distribution function for binomial distribution is

$P(X = x ) = ^nC_x * p^x * (1 -p) ^{n-x}$

Considering question a

Generally the the probability that among 12 randomly observed individuals exactly 8 do not cover their mouth when sneezing is mathematically represented as

$P(X = 8) = ^{12} C_8 * (0.267)^8 * (1- 0.267)^{12-8}$

Here C denotes combination

$P(X = 8) = 495 * 0.000025828 * 0.28867947$

$P(X = 8) = 0.0037$

Considering question b

Generally the probability that among 12 randomly observed individuals fewer than 5 do not cover their mouth when sneezing is mathematically represented as

$P(X < 5 ) =[P(X = 0 ) + \cdots + P(X = 4)]$

=> $P(X < 5 ) =[ ^{12} C_0 * (0.267)^0 * (1- 0.267)^{12-0} + \cdots + ^{12} C_4 * (0.267)^4 * (1- 0.267)^{12-4} ]$

=> $P(X < 5 ) = 0.02406 + 0.10516 + 0.21067 + 0.25580 + 0.20964$

=> $P(X < 5) = 0.805$

Considering question c

Generally the probability that fewer than half(6) covered their mouth when sneezing(i.e the probability the greater than half do not cover their mouth when sneezing) is mathematically represented as

$P(X > 6) = 1 - p(X \le 6)$

=> $P(X > 6) = 1 - [P(X = 0) + \cdots + P(X =6)]$

=> $P(X > 6)=1 - [^{12} C_0 * (0.267)^0 * (1- 0.267)^{12-0}+ \cdots + ^{12} C_4 * (0.267)^6 * (1- 0.267)^{12-6} ]$

=> $P(X > 6)= 1 - [0.02406 + \cdots + 0.0519 ]$

=> $P(X > 6) = 0.0206$

I would be surprised because the value is very small , less the 0.05

8 0

3 years ago