Answer:
a= 40-3b-c/5
a=-10+3b-2c
a=50+2b-3c/14
Step-by-step explanation:
5a+3b+c-(3b+c)=40-(3b+c)
5a=40-3b-c
5a/5=40/5-3b/5-c/5
a= 40-3b-c/5
a-3b+2c-(3b+2c)=-10-(-3b+2c)
a=-10+3b-2c
14a-2b+3c-(-2b+3c)=50-(-2b+3c)
14a=50+2b-3c
14a/14=50/14+2b/14-3c/14
a=50+2b-3c/14
Answer:
the value of 
such that there is no solution to the equation is 
.
Step-by-step explanation:
Let first simplify the expression presented on statement. The equation has no solution if and only if is eliminated in the process and an absurd is the result (i.e. 
).
To obtain an absurd, we need that 
. Hence, the value of such that there is no solution to the equation is:
Let prove the certainty of the result. We find that an absurd exist: ()
The least common multiple (or LCM) of 9 and 12 is 36
Point two one nine, however, decimals below 1 usually have a zero before the decimal point.
Answer:
27 temporary employees
Step-by-step explanation:
Given information: 30 employees, 90% temporary
To find the number of temporary employees we can do: 30*90%=30*0.9=27
There are 27 temporary employees
