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il63 [147K]
4 years ago
11

The provided diagram of triangle ABC will help you to prove that the base angles of an isosceles triangle are congruent. The fir

st step is to draw auxiliary line AO. What must be true about in order to complete the proof using the ASA (Angle Side Angle) triangle congruency theorem? Classify each statement as needed or not needed to complete the proof.
AO bisects BAC

AO is perpendicular to BC

Point O is the midpoint of BC

AO is an altitude.

answer choices are:
Needed
Not needed

Mathematics
2 answers:
Mnenie [13.5K]4 years ago
7 0

Answer:

I did this:

1. Needed

2. Needed

3. Not Needed

4. Needed

Step-by-step explanation:

klio [65]4 years ago
6 0

Answer:

AO bisects BAC - Needed

AO is perpendicular to BC  - Needed

Point O is the midpoint of BC  - Not needed

AO is an altitude - Not needed

Step-by-step explanation:

In ΔAOB,

  • <BOA = 90° (since AO is perpendicular to BC )
  • <BAO = \frac{1}{2}<BAC (since AO bisects BAC)

In ΔAOC,

  • <COA = 90° (since AO is perpendicular to BC )
  • <CAO = \frac{1}{2}<BAC (since AO bisects BAC)

In ΔAOB and ΔAOC,

  • <BOA = <COA (since both are 90°)
  • <BAO = CAO (since AO bisects BAC)
  • AO=AO

So, we can conclude ΔAOB ≅ ΔAOC (<em>ASA property</em>) and hence the base angles <ABO and < ACO of the isosceles triangle ABC are also congruent.



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MArishka [77]
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Or at least that what my calculator says.
8 0
3 years ago
THIS IS FOR 27 POINTS!!!<br> EXPLAIN PLEASE!!!!<br> Solve -9(2+a) + 4(2a+9)=11
Sindrei [870]
So,

First you have to distribute the numbers outside of the parentheses (you multiply them with the numbers inside of the parentheses

-18+(-9a) + 8a +36=11
Then collect like terms
18-1a =11
 -18    -18
---------------------
-1a=-7
Divide both sides by -1
a=7




8 0
3 years ago
Read 2 more answers
What is the answer i cant solve it 6.4u-5.1u=-3.25?
Marta_Voda [28]
I hope this helps you




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7 0
3 years ago
What is the standard form of the equation of a line for which the length of the normal segment to the origin is 8 and the normal
jeka57 [31]
Slope of line = tan(120) = -tan(60) = - &radic;3
Distance from origin = 8

Let equation be Ax+By+C=0
then -A/B=-&radic;3, or
B=A/&radic;3.
Equation becomes
Ax+(A/&radic;3)y+C=0

Knowing that line is 8 units from origin, apply distance formula
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Substitute coordinates of origin (x,y)=(0,0)  =>
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Check:
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=16/2
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Similarly C=-16 will satisfy the given conditions.

Answer  The required equations are
&radic;3 x + y = &pm; 16 
in standard form.

You can conveniently convert to point-slope form if you wish.




4 0
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sleet_krkn [62]
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8 0
3 years ago
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