2x+3y-10=0 (1)
+
4x-3y-2=0 (2)
____________
6x -12=0 (if you just want the resulting equation. It is 6x-12=0)
x=2
take x=2 and put it into equation (2)
4(2) -3y -2=0
-3y= 2-8
y= 2
(x=2,y=2)
Answer:
The answer would be HFG = KIJ (A)
If we know that the opposite and the adjacent side of the triangle are congruent, then the hypotenuse is congruent too. Therefor, A is correct as we know the opposite side and the adjacent side are congruent.
Answer:
A choice.
Step-by-step explanation:
Domain starts at x = - 7 and ends at x = 4. The domain from the graph is also continuous. Therefore, we can rule out C and D.
B is not correct as domain starts from x = -7 and not x = - 4.
Answer:
i think $25.00
Step-by-step explanation:
Answer:
The solution of the given initial value problems in explicit form is and the solutions are defined for all real numbers.
Step-by-step explanation:
The given differential equation is
It can be written as
Use variable separable method to solve this differential equation.
Integrate both the sides.
... (1)
It is given that y(1) = -2. Substitute x=1 and y=-2 to find the value of C.
The value of C is -2. Substitute C=-2 in equation (1).
Therefore the solution of the given initial value problems in explicit form is .
The solution is quadratic function, so it is defined for all real values.
Therefore the solutions are defined for all real numbers.