Number of weekend minutes used: x
Number of weekday minutes used: y
This month Nick was billed for 643 minutes:
(1) x+y=643
The charge for these minutes was $35.44
Telephone company charges $0.04 per minute for weekend calls (x)
and $0.08 per minute for calls made on weekdays (y)
(2) 0.04x+0.08y=35.44
We have a system of 2 equations and 2 unkowns:
(1) x+y=643
(2) 0.04x+0.08y=35.44
Using the method of substitution
Isolating x from the first equation:
(1) x+y-y=643-y
(3) x=643-y
Replacing x by 643-y in the second equation
(2) 0.04x+0.08y=35.44
0.04(643-y)+0.08y=35.44
25.72-0.04y+0.08y=35.44
0.04y+25.72=35.44
Solving for y:
0.04y+25.72-25.72=35.44-25.72
0.04y=9.72
Dividing both sides of the equation by 0.04:
0.04y/0.04=9.72/0.04
y=243
Replacing y by 243 in the equation (3)
(3) x=643-y
x=643-243
x=400
Answers:
The number of weekends minutes used was 400
The number of weekdays minutes used was 243
I believe the answer is 1.343 x 10^5
Answer:
This would not be an appropriate sampling technique because it is biased and it would not be fair for 60 students to choose a mascot for a school with 800 students.
Step-by-step explanation:
Answer: $18,617.75 is the answer
$87,525-$77,100=$10,425 (the amount over $77,100)
$10,425 x .28=$2,919 (the 28% taxed amount over $77,100)
$2,919+$15,698.75 (the already taxed amount in the chart)=$18,617.75
Step-by-step explanation:
Answer:
6x^8y^5
Step-by-step explanation:
(3)(2)= 6
add the exponents for the variables
