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3 years ago

I need help geometry ASAP. 30 points.

Mathematics

1 answer:

Amiraneli [1.4K]3 years ago

3 0

10a) x = 81 y = 30.5

Isolate y

2y + 20 = x

2y = x- 20

y = x/2 - 10

Plug in for y

4y - 6 + 64 + x = 180

4(x/2 - 10) - 6 + 64 + x = 180

4x/2 - 40 -6 + 64 + x = 180

4x/2 + 18 = 180

4x/2 = 162

4x = 324

x = 81

Plug in for x

2y + 20 = x

2y + 20 = 81

2y = 61

y = 30.5

10b) x = 47

Isolate x

4x -12 = 3x + 35

x - 12 = 35

x = 47

11)

2. definition of parallelogram

3. < ABD ≅ < BDC

4. < CBD ≅ <BDA

6. I'm not 100% sure what this one is but I think it has something to do with the line of symmetry.

Hope this helps! ;)

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The computers of six faculty members in a certain department are to be re- placed. two of the faculty members have selected lapt

FinnZ [79.3K]

Answer:

A) The probability that both selected setups are for laptop computers is 0.067

B)The probability that both selected setups are desktop machines is 0.4

C)The probability that at least one selected setup is for a desktop computer is 0.933

D)The probability that at least on computer of each type is chosen for setup is 0.533

Step-by-step explanation:

Number of laptops = 2

Number of desktops = 4

Total number of outcomes = 15

a) what is the probability that both selected setups are for laptop computers?

Total number of outcomes = 15

So, the probability that both selected setups are for laptop computers = $\frac{1}{15}=0.067$

b)what is the probability that both selected setups are desktop machines?

Number of desktops = 4

Number of desktops to be chosen = 4

We will use combination

No. of ways to select two desktops = $^4C_2=\frac{4!}{2!(4-2)!}=6$

So,the probability that both selected setups are desktop machines= $\frac{6}{15}=0.4$

P(at least 1 desktop)=1-P(No desktop)

P(at least 1 desktop)=1-P(both laptops)

P(at least 1 desktop)=1-0.067=0.933

So,the probability that at least one selected setup is for a desktop computer is 0.933

d) what is the probability that at least on computer of each type is chosen for setup?

No. of ways to select one desktop $=^4C_1=\frac{4!}{1!(4-1)!}=4$

No. of ways to select one laptop = $^2C_1=\frac{2!}{1!(2-1)!}=2$

So, No. of ways to select one laptop and one desktop= $4 \times 2 = 8$

So,the probability that at least on computer of each type is chosen for setup= $\frac{8}{15}=0.533$

6 0

3 years ago

A recipe for 1 batch of muffins included 2/3 cup of raisins. She made 2 1/2 batches of muffins. How many cups of raisins did she

choli [55]

Answer:

If she made 2 1/2 batches of muffins and you had 2/3 of raisins per 1 batch then you'd have a total of 1 2/3 cups of raisins

Step-by-step explanation:

1 batch= 2/3 cups

2 batches=4/3 cups or 1 and 1/3 cups

1/2 batch= 1/2 of 2/3= 1/3 cups

2 batches+1/2 batches= 1 and 1/3 cups+1/3 cups

1 and 1/3 cups+1/3 cups= 1 and 2/3 cups of raisins

3 0

3 years ago

A stalk of corn casts a shadow of 117 inches, while a 8-inch ear of corn casts a shadow of 13 inches. Use similar triangles to f

Gemiola [76]

Answer: 72

We can use ratios

117 inches / 13 inches = 9

The corn cast shadow is 9 times bigger than the example we are given.

9 * 8 = 72

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1 year ago

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nexus9112 [7]

Answer:

3c-28

Step-by-step explanation:

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3 years ago

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Solve for side AB, must show work

shutvik [7]

Cos = adj/hyp
hyp = AB
cos(25) = 7/AB
AB = 7.7

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3 years ago

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