The hydrogenation of ethyl cinnamate will result to an ester which can be a racemic mixture of products or just a meso compound depending on the structure of the ethyl cinnamate (cis or trans). The ester will produce a frequency of C=O stretch of <span>1750 - 1735 (s.</span>
The answer is I have no idea really
Answer:
atomic mass 112.4 and Cadmium (Cd)
Explanation:
You have 73.35 g of MO.
After the reaction the O is removed and you only have M which the mass is 64.21 g.
With that you can calculate the mass of O removed:
Mass of O = 9.14 g
Mass = AM * moles ; (AM : Atomic Mass)
9.14 = 16 * moles
moles = 9.14 / 16
moles = 0.57125
The formula of the metal oxide is MO, meaning it has 1 mole of M per mole of O. 73.35 had 0.57125 moles of O, then it also had 0.57125 moles of M, and the remaining mass of 64.21 g represents those moles
Mass = AM * moles ; (AM : Atomic Mass)
64.21 = AM * 0.57125
AM = 64.21/0.57125 = 112.4 amu
The metal with an atomic mass of 112.4 is Cadmium (Cd), therefore the metal oxide is CdO
Answer: 55,000
<u>Explanation:</u>
Scientific Notation: 5.5 x 10⁴
Standard form: move the decimal 4 places to the right
5 5 0 0 0 0.
= 55,000
