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butalik [34]
4 years ago
9

A car is traveling at 10 m/s. The driver sees a deer jump into the road so he slams on his brakes and the car skids to a stop. I

f the car stops over a distance of 49 m and the mass of the car and driver is 1,800 kg, what is the friction force between the tires and the road?
Physics
1 answer:
fenix001 [56]4 years ago
5 0

Answer:

1836 N

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

Equation of motion

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-10^2}{2\times 49}\\\Rightarrow a=-1.02\ m/s^2

F=ma\\\Rightarrow F=1800\times 1.02\\\Rightarrow F=1836\ N

The frictional force provided by the brakes is 1836 N

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A system consists of N particles that can occupy two energy levels: a nondegenerate ground state and a three-fold degenerate exc
cupoosta [38]

Answer:

Ng = 0.893 N,  Ne = 0.107N

Explanation:

Number of particles in Ground state = Ng

Number of particles in Excited state = Ne

Ne/Ng = e^{(-ΔE)/kt}

Since excited state is 3 fold degenerate

Ne/Ng =3 x e^{(-ΔE)/kt}

ΔE = Energy difference between ground and excited states = 0.25eV

T = 960 K

Constant k = 8.617 x 10^-5 eV/K

Ne/Ng = 3 x e^{-0.25/(8.617x10^-5) x 960}

           = 3 x e^(-3.188645)

           = 3 x 0.0412 = 0.1237 ≅ 0.12

Ne = 0.12 Ng

but Ne + Ng = N, where is N is total number of particles, substituting Ne into equation we get,

Ng(1 + 0.12) = N

Ng = N/1.12 = 0.893N

and Ne = 0.12 x 0.893 N = 0.107 N

3 0
3 years ago
A person eats a container of strawberry yogurt. The Nutritional Facts label states that it contains 255 Calories (1 Calorie = 41
Sever21 [200]

Answer:

mass = 0.44 Kg

Explanation:

given,                                                            

Calories contain in the strawberry yogurt = 255 calories

1 Calorie = 4186 J                                      

latent heat of vaporization = 2.42 x 10⁶ J/Kg

mass of perspiration = ?                      

Energy = 255 calories                      

Energy = 255 x 4186                            

            = 1067430 J                                    

Energy = mass x latent heat of vaporization

mass = \dfrac{Q}{L_v}

mass = \dfrac{1067430}{2.42 \times 10^6}

mass = 0.44 Kg                                                  

4 0
4 years ago
Which Of The Following Research Methods Are Widely Used By Psychologists?
goldenfox [79]

Answer: As you said D.

Explanation:

4 0
3 years ago
Scientists are making plans to put a probe in orbit around Earth. They want the probe to enter the orbit shown below.
iris [78.8K]

An arrow which shows the direction that the probe should be moving in order for it to enter the orbit is X.

<h3>What is an orbit?</h3>

An orbit can be defined as the curved path through which a astronomical (celestial) object such as planet Earth, in space move around a Moon, Sun, planet or star.

In this scenario, if the scientists want the probe to enter the orbit they should ensure that probe moves in direction X. This ultimately implies that, the probe must move in the same direction as the orbit, in order to enter it.

Read more on orbit here: brainly.com/question/18496962

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6 0
3 years ago
Read 2 more answers
An athlete can twirl a baton so that it reaches an angular velocity of 12 rad/s from rest in 0.5 s. If the length of a uniform b
NikAS [45]

Answer:

The torque needed is 46.08 Nm

Explanation:

Given;

angular velocity, ω = 12 rad/s

time of motion, t = 0.5 s

length of the baton, r = 0.8 m

mass of the baton, 0.5 kg

The torque needed to  reach the angular velocity is given by;

τ = F x r

where;

F is the centripetal force of the baton

r is the length of the baton = radius of the circular motion of the baton

F_c =ma_c= \frac{mv^2}{r} = m\omega^2 r

Torque is given by;

\tau = F_c *r\\\\\tau = m \omega^2 r *r\\\\\tau = m \omega^2 r^2 \\\\\tau = (0.5)(12)^2(0.8)^2\\\\\tau = 46.08 \ N m

Therefore, the torque needed is 46.08 Nm

6 0
3 years ago
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